It is: 180-42 = 138 degrees
41
8.57 degrees
32 degrees
The 42 interior angles of a regular 42-agon add up to 7200 degrees and each angle is 7200/42 which is 171.'428571' degrees recurring decimal '428571'
If it is an isosceles triangle then the base angles must be equal angles of 69 degrees because there are 180 degrees in a triangle and 42+69+69 = 180 degrees
The supplementary angle to 42 degrees is 138 degrees
42
41
90 - 42 ie 48o
21 degrees
The vertex angle of an isosceles triangle is equal to the measure of each of its base angles. Therefore, if one of the base angles measures 42 degrees, then the vertex angle also measures 42 degrees.
The complement of an angle is found by subtracting its measure from 90 degrees. For an angle measuring 48 degrees, the complementary angle is 90 - 48, which equals 42 degrees. Therefore, the complement of a 48-degree angle is 42 degrees.
8.57 degrees
To find the measure of angle HLJ, we can use the fact that the sum of the angles in triangle HLI must equal 180 degrees. Therefore, angle HLJ can be calculated as follows: Angle HLJ = 180° - (angle ILJ + angle HLI) = 180° - (42° + 45°) = 180° - 87° = 93°. Thus, the measure of angle HLJ is 93 degrees.
32 degrees
69 degrees 180-42 = 138 138/2 = 69 degrees You do not need the measure of the side to derive the answer.
Each exterior angle is 360/42 = 8.571429 degrees So each interior angle is 180 - 8.571429 = 171.4286 degrees.