A=30, B=15, H=4 A=30, B=12, H=5 A=30, B=2, H=30 1/2 b x h= Area
The total surface area of a cuboid with sides of length L, B and H is2*(L*B + B*H + H*L) square units.
A=h(b+B) divided by 2 * * * * * where A = area h = vertical height b and B are the lengths of the parallel sides.
The capacity of a cuboid with sides of length L, B and H is L*B*H cubic units.
Capacity (or Volume) = L*B*H cubic units where L = length, B = breadth and H = height.
(b+h)(b+h)= b2+2hb+h2.
b/h
There is no figure given!!!! However, In a triangle the three angles are A B & 90 degrees. The sides opposite to A,B, & 90 are 'a' , 'b' & 'h' respectively. Hence Sin A = a/h SinB = b/h CosA = a/h ( Check ; 'a/h') Csc B ( CosecantB) = 1/ (a/h) = h/a CotB = CosB / SinB = (a/h) / (b/h) = a/b
If an additional B is added to the reaction, the reaction will be more likely to proceed towards completion, as there will be more B molecules available to react with KL and H. This may lead to an increase in the amount of product formed, depending on the stoichiometry and conditions of the reaction.
You cannot. If the base is B and the height is H any of the following will give an area of 13: B = 13, H = 1 B = 130, H = 0.1 B = 1300, H = 0.01 etc. Or, B = 6.5, H = 2 B = 65, H = 0.2 etc Or B = 2.6, H = 5 B = 26, H = 0.5 etc I hope you get the idea.
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
v=B*H B= area of the Base so... v= (b*h)*h
Area of a parallelogram = b*h. Call the area of parallelogram one x and two y. We now know that x = y = b(x)h(X) = b(x)h(y). Now b(x)h(x) = b(x)h(y) b(x)h(x)/b(x) = b(x)h(y)/b(x) h(x) = h(y), so the height of the second parallelogram must equal the height of the first.
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