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Find each trigonometric ratio.Use the illustration on the right.1.sin A 2.sin B 3.cos A 4. csc B 5.cot B?
There is no figure given!!!!
However,
In a triangle the three angles are A B & 90 degrees.
The sides opposite to A,B, & 90 are 'a' , 'b' & 'h' respectively.
Hence Sin A = a/h
SinB = b/h
CosA = a/h ( Check ; 'a/h')
Csc B ( CosecantB) = 1/ (a/h) = h/a
CotB = CosB / SinB = (a/h) / (b/h) = a/b
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