Find each trigonometric ratio.Use the illustration on the right.1.sin A 2.sin B 3.cos A 4. csc B 5.cot B?

Answer 1

There is no figure given!!!!

However,

In a triangle the three angles are A B & 90 degrees.

The sides opposite to A,B, & 90 are 'a' , 'b' & 'h' respectively.

Hence Sin A = a/h

SinB = b/h

CosA = a/h ( Check ; 'a/h')

Csc B ( CosecantB) = 1/ (a/h) = h/a

CotB = CosB / SinB = (a/h) / (b/h) = a/b