The slope is 5. Parallel lines always have the same slope.
4y-8x = 12 4y = 8x+12 y = 2x+3 So the slope is 2 and the y intercept is 3
As the second line is parallel to the first then the slopes of both lines are the same. 4x + y - 1 = 0 : y = -4x + 1 : Therefore the slope is -4. Using the standard slope-intercept equation of y = mx + c for the second line gives :- 2 = -4x1 + c : 2 = -4 + c : c = 2 + 4 = 6. Therefore the equation of the second line is y = -4x + 6. (Or y + 4x - 6 = 0)
Slope = 1Y-intercept = 0Y = X
ax+by=c2x+3y=113y=-2x+11(3y=-2x+11)/3= y=-2/3x+11/3 slope intercept form5=-2/3(6)+b replace x and y with point given5=-4+b9=bthereforey=-2/3x+92x+3y=27
1, it will have the same slope but the y intercept will be different.
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
You are missing a - or + sign. The answer is 5/2 though. :)
y = 0That's the equation of the x-axis.Its slope is zero.
Your answer can vary as long as it has a slope of 1. So it could be y=x+(insert number here)
The slope would be 3/4
If you mean: y = 0.5x-10 then an equation parallel to it will have the same slope of 0.5 but a y intercept different to -10
1.67 or 1.667