I know the answer you are looking for is a right triangle, but the way you worded the question is an example of absolutely horrible grammar, logic and reason. The concept you are struggling with is the Pythagorean theorem. A squared + B squared = C squared. Aaarrrgh! Just think of 3,4,5. 3x3=9 and 4x4=16.
9 +16=25.
5x5 = 25.
If one side of a triangle is 3 ft. and another side is 4 ft then we know the long side is 5 ft. Use a ruler draw it out. Thank a Greek guy named Pythagoras.
The forumal for finding the finding the length of the hypotenuse of a right triangle is square root of a squared plus b squared equals c. The letters a and b are the two sides that the length is known and the c is the unknown side.
a squared plus b squared equals c squared usually expressed as: a2+b2 = c2
No, according to to the Triangular Inequality, A+B can never be larger than C.==========================Opinion #2:It seems to me that A+B must be larger than C,otherwise you can't make a triangle with them.
That it is a right triangle with the longest side c facing the right angle.
A triangle with side a: 5, side b: 8, and side c: 11 units has an area of 18.33 square units.
C Square
(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac
The forumal for finding the finding the length of the hypotenuse of a right triangle is square root of a squared plus b squared equals c. The letters a and b are the two sides that the length is known and the c is the unknown side.
Pythagorean's theorem: Length of Side A squared times the length of Side B squared equals the length of Side C squared in a right triangle. A2+B2=C2
b+b+b+c+c+c+c =3b+4c
b + b + b + c + c + c + c = 3b + 4c
If A is the area of a triangle with side length a, b and c and s is (a+b+c)/2 ( known as the semiperimeter of the triangle) Then, Heron's formula tells us that A=square root of [s(s-a)(s-b)(s-c)].
the area of a triangle A= Square root of s(s-a)(s-b)(s-c)
a squared plus b squared equals c squared usually expressed as: a2+b2 = c2
Yes.
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
It's the square root of a2+b2. It cannot be simplified. It is NOT a+b. The answer is c square.