Q: What is each angle's size in a 30 sided polygon?

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170.27 degrees

Pick a point around the center of the polygon. Join each vertex to this point. You will now have 10 triangles. The total angle of these 10 triangles is 10x180 degrees. Now you need to subtract the angles of the ten triangles at the center (which is 360 degrees). Therefore total internal angles is (10x180)-360 = 1800-360 which is 1440 degrees. A 10 sided polygon has 20 internal angles. So each angle would be 1440/20 = 144/2 = 72 degrees

Providing that it is a regular 15 sided polygon then each interior angle will be 156 degrees

Each interior angle of the regular 8 sided octagon measures 135 degrees

Sum of the interior angles of a n-gon = (n-2)*180 degrees. So, for a polygon with 20 sides, the sum og the 20 interior angles is (20-2)*180 = 18*180 = 3240 degrees. Since it is a regular polygon, all interior angles are equal, and each one is 3240/20 degrees = 162 degrees.

Related questions

It All depends how big it is

152.307692 repeating degrees

The exterior angles of any polygon add up to 360. 360/15 = 24

30 degrees

If it is a regular 12 sided polygon then each interior angle is 150 degrees.

If its a regular polygon then its 147 degrees.

Each angle would be 170.27027 degrees. The total sum of all interior angles is 6300 degrees. This shape is called a triacontakaiheptagon.

The sum of the angles of a polygon is equal to 180Â° times (n-2) where n is the number of sides.For a 23-sided polygon, that would give a total of (180Â°) x (21) = 3780Â°. If the angles are all the same, each would be 3780Â° Ã· 23 = 164.3478Â°

170.27 degrees

158.82 degrees

150 degrees each

The question can be answered only if the 20-gon is regular - ie all its angles are the same. IF that is the case, then: The sum of the exterior angles of any polygon is 360 degrees. Since there are 20 exterior angles, each of them must be 360/20 = 18 degrees.