The exterior angles of any polygon add up to 360.
360/15 = 24
30 degrees
The sum of the exterior angles of a polygon is 360°. There are the same number of exterior angles as there are sides. For a regular polygon all the angles are the same size: → number_of_sides × exterior_angle = 360° → exterior_angle = 360° ÷ number_of_sides → exterior_angle = 360° ÷ 5 = 72°
360 / 9 = 40
Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees
The exterior angles of any polygon add up to 360. 360/8 = 45
30 degrees
The question can be answered only if the 20-gon is regular - ie all its angles are the same. IF that is the case, then: The sum of the exterior angles of any polygon is 360 degrees. Since there are 20 exterior angles, each of them must be 360/20 = 18 degrees.
It All depends how big it is
The sum of the exterior angles of a polygon is 360°. There are the same number of exterior angles as there are sides. For a regular polygon all the angles are the same size: → number_of_sides × exterior_angle = 360° → exterior_angle = 360° ÷ number_of_sides → exterior_angle = 360° ÷ 5 = 72°
360 / 9 = 40
Exterior angles are 7.5 There are 48 sides.
152.307692 repeating degrees
Exterior angles are supplementary with interior angles, so 180-30=150
The sum total of all exterior angles of any polygon is 360 degrees. So if you're given thevalue of one exterior angle AND THE POLYGON IS REGULAR(all exterior angles are thesame size), all you have to do is divide the size of one angle into 360, and the quotientis the number of sides.
The exterior angle of a 7 sided shape add up to 360 degrees The interior angles of a 7 sided shape add up to 900 degrees
Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees
The exterior angles of any polygon add up to 360. 360/8 = 45