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The terms in row 29 are:

29Cr = 29!/[r!*(29-r)!] for r = 0, 1, 2, ... 29

where r! denotes 1*2*3*...*r

and 0! = 1

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Related Questions

What is the 5th row on pascals triangle?

1,4,6,4,1


What is the sum of the numbers in the 5th row of pascals triangle?

depends. If you start Pascals triangle with (1) or (1,1). The fifth row with then either be (1,4,6,4,1) or (1,5,10,10,5,1). The sums of which are respectively 16 and 32.


What is the sum of the 4 th row of pascals triangle?

The sum is 24 = 16


How is the pascal triangle and the binomial expansion related?

If the top row of Pascal's triangle is "1 1", then the nth row of Pascals triangle consists of the coefficients of x in the expansion of (1 + x)n.


What numbers are in the fifth row of pascals triangle?

1 5 10 10 5 1


What is the sum of fifth row of Pascals triangle?

The Fifth row of Pascal's triangle has 1,4,6,4,1. The sum is 16. Formula 2n-1 where n=5 Therefore 2n-1=25-1= 24 = 16.


What is row ten of pascals triangle?

1, 9, 36, 84, 126, 126, 84, 36, 9, 1


What is the sum of the 100th row of pascals triangle?

Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.


What is the sum of the 17th row of pascals triangle?

The sum of the 17th row of Pascal's Triangle can be calculated using the formula 2^n, where n is the row number minus one. In this case, the 17th row corresponds to n=16. Therefore, the sum of the 17th row is 2^16, which equals 65,536.


How many odd numbers are in the 100th row of Pascals triangle?

The number of odd numbers in the Nth row of Pascal's triangle is equal to 2^n, where n is the number of 1's in the binary form of the N. In this case, 100 in binary is 1100100, so there are 8 odd numbers in the 100th row of Pascal's triangle.


Examples of Pascals triangle?

Pascal's triangle


What is the answer to 10c3 using pascals triangle?

To find (10C3) using Pascal's Triangle, locate the row corresponding to (n=10). The entries in this row represent the binomial coefficients for (n=10). The third entry (starting from (0)) in this row corresponds to (10C3), which is (120). Thus, (10C3 = 120).

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