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Q: What is the sum of fifth row of Pascals triangle?

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The Fifth row of Pascal's triangle has 1,4,6,4,1. The sum is 16.

Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.

No. It's n^2

Pascals triangle is important because of how it relates to the binomial theorem and other areas of mathematics. The binomial theorem tells us that if we expand the equation (x+y)n the result will equal the sum of k from 0 to n of P(n,k)*xn-k*yk where P(n,k) is the kth number from the left on the nth row of Pascals triangle. This allows us to easily calculate the exponential of binomials without ever having to resort to expanding term by term. In addition, the way that the triangle is constructed allows us to observe that P(n,k) is always equal to nCk or n choose k. While this may not seem important, you often need to calculate combinations in Statistics and Pascals Triangle provides one of the easiest ways to calculate a large number of combinations at once.

The sum of the interior angles of a triangle is always equal to 180o.

Related questions

depends. If you start Pascals triangle with (1) or (1,1). The fifth row with then either be (1,4,6,4,1) or (1,5,10,10,5,1). The sums of which are respectively 16 and 32.

The sum of the 20th row in Pascal's triangle is 1048576.

the sum is 65,528

The sum is 24 = 16

28354132 is the correct answer, I believe.

The Fifth row of Pascal's triangle has 1,4,6,4,1. The sum is 16.

Sum of numbers in a nth row can be determined using the formula 2^n. For the 100th row, the sum of numbers is found to be 2^100=1.2676506x10^30.

Each number in Pascal's triangle is used twice when calculating the row below. Consequently the row total doubles with each successive row. If the row containing a single '1' is row zero, then T = 2r where T is the sum of the numbers in row r. So for r=100 T = 2100 = 1267650600228229401496703205376

The sum of the numbers on the fifteenth row of Pascal's triangle is 215 = 32768.

The sum of the numbers in each row of Pascal's triangle is twice the sum of the previous row. Perhaps you can work it out from there. (Basically, you should use powers of 2.)

Each element of a row of pascal's triangle is the sum of the two elements above it. Therefore when you some the elements of a row, each of the elements of the row above are being summed twice. Thus the sum of each row of pascal's triangle is twice the sum of the previous row.

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