The angle between the two hands changes constantly at the rate of 5.5° per minute. This formula finds the angle between the two hands for a given time (h:m) taking the absolue value as shown: |5.5m - 30h| If the result is greater than 180°, subtract it from 360° to get the included angle.
At 3 hours 45 minutes there is not an acute angle between the hands of the clock (unless you extend the hands backwards).
150
Angle between the hands of a clock=|11M-60H|/2i.e. M-Minutes=35(here)H- Hours=7(here)∴ The angle b/w hands of a clock=|11*35-60*7|/2=17.5°
90 degrees
At exactly 1 o'clock, the hour hand will be at an angle of 30 degrees, and the minute and second hands will be at an angle of 0 degrees.
Each minute is six degrees.
360 times
At 12 o'clock, the minute hand points at 12, and the hour hand also points at 12. Since both hands are aligned, the angle between them is 0 degrees. Therefore, the angle between the hands of a clock at o'clock is always 0 degrees.
360
24
Each minute is 6 degrees and so it's about 30 degrees
No, the size of each angle formed by the hour and minute hands on a clock would not change if the minute hand were shorter. The angles are determined by the positions of the hands relative to each other and the clock face, not by their lengths. Therefore, regardless of the minute hand's size, the angles between the hands remain the same.
144 degrees. Each minute mark around the clock face is 6 degrees.
It is a obtuse angle.
At 3 hours 45 minutes there is not an acute angle between the hands of the clock (unless you extend the hands backwards).
22215 pm is not a correct time, what time do you mean? The angle between the hands, if that is what you mean by 'the angle of the clock', does not depend on the length of the hands, so why have you given them? Please make the question clear and resubmit.
At 3:00 (1500 hours) on a clock, the hour hand is pointing directly at the 3 and the minute hand is pointing at the 12. To find the angle between the hands, we can use the formula: |(30*H) - ((11/2)M)|, where H is the hour and M is the minute. Plugging in the values, we get |(303) - ((11/2)*0)| = |90 - 0| = 90 degrees. Therefore, the angle between the hands of the clock at 1500 hours is 90 degrees.