This problem can be solved as follows: The angle Ah of the hour hand of a clock, measured from the position at noon or midnight when the hour and minute hands exactly coincide, is Ah = (360 degrees/12 hours)th, where th is the time in hours, including fractions of hours, because the hour hand moves the entire 360 degrees around the clock in 12 hours. Similarly, the angle Am of the minute hand = (360 degrees/60 minutes)tm, where tm is the time in minutes only, including fractions of minutes. The stated time is 3 + 40/60 + 20/3600 hours = 3.672222... hours and the angle is therefore about 110. 11666666... degrees, using the formula above. The time in minutes only is 40 + 20/60 = 40.33333...., so that the angle of the minute hand is 242 degrees. The difference between them is therefore about 131.833..... degrees, or in fraction form 131 and 5/6.
At 3 hours 45 minutes there is not an acute angle between the hands of the clock (unless you extend the hands backwards).
There is no angle "between" one hand of a clock.
Angle between the hands of a clock=|11M-60H|/2i.e. M-Minutes=35(here)H- Hours=7(here)∴ The angle b/w hands of a clock=|11*35-60*7|/2=17.5°
150
90 degrees its just like the angle between 6 and 9 on a clock basically for every number its 30 degrees
At 3 hours 45 minutes there is not an acute angle between the hands of the clock (unless you extend the hands backwards).
Right Angle or 900
The angle - is 120 degrees !
180o
It creates a 150o angle at 3:40
There is no angle "between" one hand of a clock.
Angle between the hands of a clock=|11M-60H|/2i.e. M-Minutes=35(here)H- Hours=7(here)∴ The angle b/w hands of a clock=|11*35-60*7|/2=17.5°
clock, stopwatch, watch
Doc Clock
It is a obtuse angle.
Qa in Babylon. Qa = the volume of the water flowing from and into the water clock.
With the graphic facilities available on this site, I do not stand a chance! However, if you look at an analogue clock, a 25 degree angle is one between 12 (at the top of the clock) and 81/3 minutes.