The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
The area of a regular hexagon with side lengths of 8cm is about 166.3cm2
309.12
By Apothem LengthThe area of a regular octagon can also be computed using its measured apothem (a line from the center to the middle of any side). The formula for an octagon with side length s and apothem a is Area = a4s . (apothem times one-half the perimeter)So for this example, (8 cm and 9.66 cm) Area = (9.66)(32) = 309.12 cm2----By Side LengthThe area of a regular octagon with side length s is given as Area = 4.828427 s2 , so for a regular octagon of side length 8 cm , the area is calculated as 309.02 cm2. (indicating an error from rounding the apothem length)(This formula is generated by adding or subtracting the missing corner triangles.)
The area is 212.1 square feet.
It is 665.1 sq inches.
665.1 square units.
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
4 times the square root of 3. Use an equilateral triangle and 30-60-90 triangles.
9762
It probably is a regular hexagon. Take the Apothem (The distance from the center to a side) and multiply by one half and by the perimeter. if the sum of interior angles of a polygon is 120 then (n-2)180=120==>n=8/3 which is impossible
A regular hexagon, like any other hexagon, has six sides.
penis salad
The area of a regular polygon with n sides is the half of the product of its perimeter and the apothem. So that you do not have enough information to find the area of the polygon (for example how many sides it has, or the side length).
Radii are related to circles.What do you mean by an "...octagon with a radius..."?Unless the octagon is regular it is impossible to to calculate the area of the octagon from one measurement alone.So assuming that the octagon is a regular octagon, what do you mean by radius? Do you mean:the radius of the circumcircle which passes through all verticesarea regular octagon = 8 × ½ × 8 × 8 × sin(360°/8) units² = 256 × sin(45) units²= 256 × 1/√2 units²= 128√2 units²≈ 181 units²the radius of the inscribed circle, which is the apothem of the octagonarea regular octagon = 8 × 8 × 8 × tan((360°/8)/2) units² ≈ 196 units²Something elseRe-ask your question explaining what you mean by "radius".
== == The question does not make sense because the numbers are not consistent. It is a bit like asking the area of a circle if the radius is 6 and the diameter is 8. A circle's diameter is constrained to be twice the size of the radius. Similarly, the apothem of the specified pentagon is constrained to be a particular size and the apothem size is not 6.Also, a pentagon does not have a radius, so that part of the question does not make sense.Notes: * A previous version of the answer to this question on this site mentioned that the source of the solution is from www.icoachmath.com. However, there does not seem to be any pentagon area problems on that site. * A precise regular pentagon area is defined on the linked site:knol.google.com/k/scot-ellison/area-of-a-regular-pentagon