2
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
9 radical din 2
If we factor 60, we get 60 = 2 * 2 * 3 * 5 So sqrt ( 60 ) = sqrt (2 * 2 * 3 * 5) = sqrt (2 * 2) * sqrt (3 * 5) = 4 * sqrt( 15 ) ____________________________________________________________ actually if you do by just using the simpler way you should get 2 radical 15 since , 60 has the closest perfect square of 4 and non perfect of 15 this is how you should solve radical 60 = radical 4 times radical 15 radical 60 = simplify the 4 to 2 and leave radical 15 So , radical 60 = 2 radical 15 not what is above .
D.2√3
There is no reasonable radical approximation for radical 11.
10*radical(2).
-3*radical(2)*radical(50) = -3*radical(2*50) = -3*radical(100) = -3*10 = -30
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
There is no radical to simplify!
Ahh ok radical 40 is equal to 2 radical 10
14.14213562 or 10 rad 2 which is 10 radical sign and 2 underneath the radical sign.
40
√32 * √20 = √(32*20) = √(640) = √(2*2*160) = 2√(160) = 2√(2*2*40) = 4√(40) = 4√(2*2*10) = 8√10
In radical form, 3* sqrt(41). The decimal approximation is 19.20937271.
The square root of 100 is 10
sqrt(160) sqrt(4^2 * 10) = 4sqrt(10) -------------------simplest radical form