To find the area of a triangle given the lengths of its three sides (a, b, and c), you can use Heron's formula. First, calculate the semiperimeter (s) of the triangle using the formula s = (a + b + c) / 2. In this case, a = 10 cm, b = 5 cm, and c = 8 cm, so s = (10 + 5 + 8) / 2 = 11.5 cm. Next, calculate the area using Heron's formula: Area = √[s(s-a)(s-b)(s-c)]. Plugging in the values, we get Area = √[11.5(11.5-10)(11.5-5)(11.5-8)] = √[11.51.56.5*3.5] = √(381.9375) ≈ 19.54 square cm.
The area of a right-angled triangle with base 8 cm and hypotenuse 10 cm is: 24 cm2
area of rectangle = l * b area = 8 * 5 =40 m ^2 ( 1 m=100 cm 500cm= 5 m)
20cm squared
Volume: 8*10*12.5 = 1000 cubic cm
A square with a side length of 8 cm has an area of 64 cm2
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The area of a right-angled triangle with base 8 cm and hypotenuse 10 cm is: 24 cm2
If the area of the square is 64 square cm then its sides are 8 cm. Its perimeter: 8+8+8+8 = 32 cm
Trapezoid Area = (1/2)(b1 + b2)(h) We have: b1 = 6cm b2 = 8 cm h = 5 cm Substitute the given values into the area formula: Trapezoid Area = (1/2)(b1 + b2)(h) Trapezoid Area = (1/2)(6 cm + 8 cm)(5 cm) Trapezoid Area = (1/2)(14 cm)(5 cm) Trapezoid Area = (7 cm)(5 cm) Trapezoid Area = 35 cm^2
8+10+8+10= 36 cm
5x2= 10 8x2=16 10+16=26 perimeter= 26!
area of rectangle = l * b area = 8 * 5 =40 m ^2 ( 1 m=100 cm 500cm= 5 m)
area = 8*5 = 40 square cm
By unit of length and distance and conversion ,we can say that 1 cm=10 mm 8 cm =80 mm now ,ratio is 80 :5 16 :1 16 times does 8 cm go into 5 mm
8 cm Check: 2(5*6) + 2(5*8) + 2(6*8) = 236 cm2 Solved by using algebra.
20cm squared
40sq cm