A square of perimeter 32cm has 4 sides of length 8cm. Area = Side1*Side2 Area = 8cm*8cm Area=64cm2
64 centimeters squared
Not too sure of the question but if one side is 8 cm then its height must be 3 cm because:- Area of the triangle is: 0.5*8*3 = 12 square cm
A = Pi(r)2: A circle with a radius of 8 cm has an area of 201.06 square cm.
A diagonal of a square measures: Side X sqrt(2).Approximately (8 cm) X (1.414) = 11.312 cm
Side of square = sqrt(64) = 8 cm
If the side of 8 is double to 16 then its area is 16*16 = 256 square cm
If that means (2 times 4) then the area of the square is 8*8 = 64 square cm
perimeter of square = 4 * side side =32/4 =8 m area of square=side * side =8* 8 =64 cm ^ 2
The area of square is : 1024.0
64 centimeters squared
The area of square is : 1936.0
Area of the square: 8 times 8 = 64 square cm
If the area of the square is 64 square cm then its sides are 8 cm. Its perimeter: 8+8+8+8 = 32 cm
A triangle with side a: 8, side b: 11, and side c: 15 cm has an area of 42.85 square cm.
Assuming the base is square, then: The area of the two bases = 2 x 8 x 8 = 128 cm The area of the four side areas = 4 x 8 x 12 = 384 cm Total area = 128 + 384 = 512 cm
A square with sides of 8 cm will have an area of 64 square cm.