What is the area of a parallelogram with a circle inside the base of the parallelogram is 9 and the diameter of the circle is 6?

Answer 1

Since the area of the circle would be multiplied due to the circumference of the pathogenic therum,so you would multiply 54x2=108.Then multiply that by 54,which is the absolute value of the area of the parallelogram,so 54x108,is 5832,which you'd find the square root of,76.4. :)