The area of a circle if the diameter was s 7ft is 38.48ft
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Semicircle
For a circle inside a square, the diameter is the same as the side length, and the area of the circle is about 78.54% of the square's area (pi/4). A(c) = 0.7854 A(s) The area of the square is L x L. (For a square, L = W). The area of the circle is PI x R^2, where R = L/2. Let's express the area of the square using A = L x L = (2R) x (2R) = 4 R^2 So, the ratio of the area of the circle to that of the square is: pi/4 or about 0.7854.
S=pi x dxD S=3.14 x 3 x 40,82 S=384,5244 or rounded 385 mm
The barrel is probably much like a cylinder. All surface area is the lateral area+the area of the base(s). In this case: SA=(d)("pi")(h)+(2)("pi")(r2) SA is surface area d is diameter of the circle base h is the height r is the radius of the base What you are doing with this equation is figuring out the circumference x the height, so you get the area of the tall part. Then you take the area of one of the bases and multiply it by 2.
Area = πSr + πr² Where: S = the slant length of the cone r = radius of the base πr² = area of the base of the cone πSr = area of outside of cone -------------------------------------------------------------- The surface area of the cone is the sum of the area of the base and the slanted surface. The area of the base is the area of a circle = πr² The area of the slanted surface can be calculated by realising that if the slanted surface is cut by a straight line from the apex to the base it can be "unrolled" into a sector of a circle. Thus it is a fraction of the area of a circle. The length of the circumference of the sector is the length of the circumference of the base of the cone; the length of the whole circle from which this is a sector is the circle with radius of the slant height of the cone; thus: area slanted surface = πS² × ((2πr)/(2πS)) = πSr Thus the surface area of a cone = area base + area slant surface → surface_area_cone = πr² + πSr = πr(r + S) where r is the radius of the base and S is the slant height.