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Q: What is the area of a rectangle that has a length of 38 and a width of 28?

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Length 7 inches and width 4 inches because 7*4 = 28 square inches

The area of rectangle is : 952.0

Multiply width by length to get the area. The answer would be 28 square feet.

14 units.

All that can be said for sure is that length + width = 56. The rectangle could be 2 x 28, 4 x 14, 7 x 8 and those are only the whole-number dimensions...

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Area = length x width Area = 28 x 358 Area = 10,024

Area = Length *Width = 28*4 = 112 sq cm

Area=Length*Width A=14 Inches*2 Inches A= 28 square inches or 28 in2

35 and 28

The area of rectangle is : 28.0

28

It is: 4*7 = 28 square cm

Length 7 inches and width 4 inches because 7*4 = 28 square inches

Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.

Assuming there is no border around the circle, then doubling the radius will give the length and width of a square (28 x 28 = 784cm2). The problem in your question is that you state it is a rectangle. Which means that the rectangle must be longer in length then width!

In order to make sense of this question it is necessary to assume that the area is 28 SQUARE metres and not 28 metres as stated. Then, Length = Area/Width = 28/4 = 7m Then perimeter = 2*(Length + width) = 2*(7 + 4) = 2*11 = 22 metres.

Factors of 28 include 7 x 4. 7 is 1 less than twice 4...

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