0
What is the area of a rectangle whose dimensions are in the ratio of 5 to 12 with a diagonal of 17.55 cm showing all aspects of work?
Wiki User
∙ 10y ago
1 Let the sides be 5x and 12x
2 Using Pythagoras: (5x)2+(12x)2 = 17.552
3 And so: 25x2+1442 = 308.0025 => 1692 = 308.0025
4 Divide both sides by 169 and then square root both sides
5 Therefore: x = 1.35 so sides are 5*1.35 = 6.75 cm and 12*1.35 = 16.2 cm
6 Area = 6.75*16.2 = 109.35 square cm
7 Check with Pythagoras: 6.752+16.22 = 308.0025 and its square root is 17.55 cm which is the rectangle's diagonal
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
What type of data figure is good for showing complex processes of ideas?
a diagram
What type of data figure is good for showing complex processes or ideas?
diagram
What is the area of a triangle whose dimensions are 30 by 24 by 30 feet showing all work and answer to the nearest square yard?
Change the feet into yards and use Pythagoras' theorem to find its perpendicular height; It is an isosceles triangle which is 2 right angle triangles joined together Height is square root of (10^2-4^2) = 2 times square root of 21 Area: 0.5*8*(2 times square root of 21) = 110 square yards rounded
What mathematical relationship between variables is suggested by a graph showing a half-parabola?
inverse linear or quadratic
What is the volume of a cuboid that has length of 8 cm and a width of 5 cm having a surface area of 197 square cm showing work?
Volume=length*width*height Length and width is given.Assume height is x. Imagine 3d shape.With length and width we can get area of two faces. 8*5=40cm2 40*2=80cm2. 197-80=117cm2 Opposite faces have same dimensions 2[X*8]+2[X*5]=117 Solve the equation. X=4.5cm So volume 4.5*8*5=180cm3
What is the area of a rectangle that has a perimeter of 61.18 cm and a diagonal of 226.1 mm showing work and answer?
The area of rectangle is : 13832.797999999999
What is the perimeter of a rectangle whose diagonal is 17.55 cm with an area of 109.35 square cm showing key aspects of work?
Here are the key aspects of work; I'll leave the details of the calculation to you. 1) Write an equation for the area, in terms of variables "w" and "h" (for width and height). 2) Write an equation for the length of the diagonal, in terms of "w" and "h". (Hint: Use the Pythagorean Theorem.) 3) Solve the two equations. 4) Calculate the perimeter, based on length and width.
What is the length of the diagonal of a rectangle whose dimensions are in the ratio of 3 to 4 with with an area of 369.63 square cm showing work?
Well, you can do your own homework, but here is the general outline of what you must do. Use the variable "x" to express the width of the rectangle. In that case, because of the ratio, the length will be (4/3)x. Write an equation for the area of the rectangle, replace x, (4/3)x and the known area, and solve for "x". (Since a quadratic equation will give you two solutions, you will obviously accept the positive solution.) Once you calculate "x", you can easily calculate the other side of the rectangle, as (4/3)x. Finally, use the Pythagorean Theorem to calculate the diagonal. Another Answer:- 1 Let the dimensions be 3x and 4x 2 So 3x*4x = 369.63 or 12x2 = 369.63 3 Divide each side by 12 and then square root each side 4 Therefore: x = 5.55 and dimensions must be 16.65 by 22.2 5 Using Pythagoras: 16.652+22.22 = 756.9025 and its square root is 27.75 6 Answer: length of diagonal = 27.75 cm
What is the perimeter of a rectangle which has a diagonal of 8.50 cm and an area of 3000 square mm showing work with answer?
Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.
What is the diagonal length of a rectangle whose area is 212.268 square cm with a perimeter of 61.18 cm showing all work with answer?
Let the dimensions of the rectangle be x and y and divide its perimeter by 2:- So: x+y = 30.59 => y = 30.59 -x Area: xy = 212.268 => x(30.59 -x) = 212.268 It follows that: 30.59x - xsquared -212.268 = 0 Solving the quadratic equation: x = 19.95 or x = 10.64 By substitution: x = 19.95 and y = 10.64 Using Pythagoras: 19.95squared+10.64squated = 511.2121 The square root of 511.2121 is 22.61 cm which is the diagonal length
What are the dimensions of a rectangle that has a perimeter of 19.8 cm and an area of 24.3 square cm showing work?
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
What is perimeter of a rectangle that has a diagonal of 8.50 cm and an area of 3000 square mm showing work with a given valid numerical answer?
The diagonal is 8.5 cm and the area is 30 square cm.Let the dimensions be x and y that have been squared and square the diagonal and the area.Using Pythagoras: x+y = 72.25 => y = 72,25-xArea: xy = 900 => x(72.25-x) = 900So it follows: 72.25x - xsquared -900 = 0Solving the quadratic equation: x = 56.25 or x = 16Square root of both number: x = 7.5 and 4By substitution: x = 7.5 and y = 4Perimeter: 2(7.5+4) = 23 cmCheck: 7.5*4 = 30 square cm which is the same as 3000 square mm
What is the area of a rectangle that has a perimeter of 61.18 cm and a diagonal of 226.1 mm showing key stages of work?
The area of rectangle is : 13832.797999999999
What is the area of a rectangle which has a diagonal of 17.55 cm and a perimeter of 459 mm showing all work?
The area of rectangle is : 8055.450000000001
The generic equation suggested by a graph showing a diagonal line from the lower left to the upper right of the graph?
y = ax
What are the dimensions of a rectangle that has an area of 600 square cm and a perimeter of 1 m showing work?
I suggest that you do the following:* Convert the meters to centimeters, to have compatible units.* Write the equation for the area of the rectangle. Replace the variable "a" (area) with the known area.* Write the equation for the perimeter of a rectangle. Replace the variable for the perimeter with the known perimeter (in cm).* Use any method to solve the simultaneous equations.Another Answer:-Let the dimensions be x and yIf: 2x+2y = 100 then x+y = 50 and x = 50-yIf: xy = 600 then (50-y)y = 600 and so 50y-y2-600 = 0Solving the quadratic equation: y = 20 or y = 30Therefore by substitution the dimensions are: when y = 20 cm then x = 30 cm
What mathematical relationship between variables is suggested by a graph showing a diagonal line from the lower left to the upper right of the graph?
Linear
