To find the area of a regular hexagon with side length of 40cm, consider that since it is regular, then it consists of 6 equilateral triangles of side 40cm. Half of each of those triangles is a right triangle. By the pythagorean theorem, we know that if the hypotenuse is 40cm, and one side is 20cm, then the other side is the square root of (40cm squared - 20cm squared) or about 34.64cm. That makes the area of each of those 12 right triangle to be about 692.8cm, so the total area of the hexagon is about 8313.8cm.
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Side length is about 58cm and the perimeter is about 348cm
Length of one side squared x 1.5 x square root of 3, for a REGULAR hexagon.
The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.Click once to select an item at the bottom of the problem.
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
The area of a regular hexagon with a perimeter 120m is about 1039.2m2