The area of a reagular hexagon with the side length of 10 is 51.96 square units
The area of a regular hexagon with side lengths of 10 units is about 259.8 units2
The area of a regular hexagon is given asA = (3*root 3)/2*t = approx 2.59807621 * tWhere A = Area and t = edge length.so if t = 10then A = 2.59807621 * 10 = 25.9807621
259.8 units2
area = 3 x (radius to point) squared x sin 60 degrees =3(10)(10)(.866) = 259.8 sq m
The area of a reagular hexagon with the side length of 10 is 51.96 square units
The area of a regular hexagon with side lengths of 10 units is about 259.8 units2
The area of a regular hexagon is given asA = (3*root 3)/2*t = approx 2.59807621 * tWhere A = Area and t = edge length.so if t = 10then A = 2.59807621 * 10 = 25.9807621
259.8 units2
area = 3 x (radius to point) squared x sin 60 degrees =3(10)(10)(.866) = 259.8 sq m
A square with a side length of 10 inches has an area of 100 square inches.
If the perimiter is 20 and one side is [[length]] then the other side is (10 - [[length]]). So the area is: [[length]] x (10 - [[length]]) square metres.
Area of hexagon= Area of original triangle/10
I assume you mean the relationship between the length and the area. Indeed, it is non-linear. The increase in area is proportional to the square of the length of the side. For example, if the length of the side is increased by a factor of 10, the area is NOT increased by a factor of 10, but by a factor of 100.
We don't need the measure of the radius since we know the measure length of the side and of the apothem, which we use to find the area of one of the triangles that are formed by connecting the center with the vertices of the hexagon. So, A = 6[(1/2)(11 x 9)] = 297 m2
The area of one side is square root (10).
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.