Q: What is the area of a square with a side length of 3x?

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2

the length of a side is x. (3x)(x)

x^2=3x(x-2)

If we express the shortest side as x, then the rectangle's length is 3x (as it is 3 times as long as its width).To find the area multiply the length and witdh together.x * 3x = 3x2The area of the rectangle would be 3x2.e.g if the width of the rectangle was 4, the area would be:3 x 42 = 48

16 sq cm. Suppose the original square had sides of x cm. Then the folded rectangle has pairs of sides of length x and x/2 cm. The perimeter is 2(x + x/2) = 3x. So 3x = 12 so that x = 4 and the area of the original square, with sides of 4 cm is 16 sq cm.

Related questions

The area of square is : 9.0

The square is formed from a wire the length of 3x, which forms a perimeter of the same length. Because each side of the square is one fourth of the total perimeter (1 out of 4 equal sides), each side is 3x/4. The square of one side of a square is equal to the area of that square, so the area is (3x/4)2 = (9/16)x2.The answer is then A = (9/16)x2.

2

If the other side is x metres, then the area is 3*x = 3x sq metres. So 3x = 18 and so x = 6 metres.

the length of a side is x. (3x)(x)

We have to assume that this rectangle is a square as only one side's length is provided so 3X 3 = 9 cm^2

7

9x^2 + 6x + 1

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I think it's 12x square.

x^2=3x(x-2)

Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.