What is the area of a square with a side length of 4x^3
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The area of a square is calculated by squaring the length of one of its sides. In this case, the side length is 3x. So, the area of the square would be (3x)^2 = 9x^2. Therefore, the area of a square with a side length of 3x is 9x^2 square units.
Well, honey, the area of a square is just the side length squared. So in this case, the area would be (3x)^2, which simplifies to 9x^2. So, darling, the area of a square with a side length of 3x is 9x^2.
Oh, what a happy little question! To find the area of a square, you simply multiply the length of one side by itself. So, for a square with a side length of 3x, the area would be (3x) * (3x) = 9x^2. Isn't that just a delightful little calculation?
Oh, dude, it's like super simple. The area of a square is just the side length squared, so for a square with a side length of 3x, the area would be (3x)^2, which simplifies to 9x^2. Easy peasy, lemon squeezy.
The area of a square is side^2. The area of a square with the side 3x is (3x)^2, or 3x times 3x = 9x^2.
2
the length of a side is x. (3x)(x)
x^2=3x(x-2)
If we express the shortest side as x, then the rectangle's length is 3x (as it is 3 times as long as its width).To find the area multiply the length and witdh together.x * 3x = 3x2The area of the rectangle would be 3x2.e.g if the width of the rectangle was 4, the area would be:3 x 42 = 48
16 sq cm. Suppose the original square had sides of x cm. Then the folded rectangle has pairs of sides of length x and x/2 cm. The perimeter is 2(x + x/2) = 3x. So 3x = 12 so that x = 4 and the area of the original square, with sides of 4 cm is 16 sq cm.