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What is the area of a square with a side length of 4x^3
Suppose the side of the square is x cm.Then its perimeter is 4x cm.The perimeter of the square is 3 cm more than that of the triangleso the perimeter of the triangle is 4x - 3 cm.Also, if the side of the square is x cm, the side of the triangle must be x + 112 cm.Then its perimeter must be 3*(x + 112) = 3x = 336 cm.Equating the two expressions for the perimeter of the triangle,4x - 3 = 3x + 336therefore x = 339 cm.The square has sides of 339 cm and a perimeter of 1356 cm.The triangle has sides of 451 cm and a perimeter of 1353 cm.
Let x be the side of the triangle. Thus 4(x-5) is the perimeter of the square.Balance by the perimeter relation,3x = 7+4(x-5)Solve for x,x = 13 inches
Find the perimeter of the triangle with sides of length x, 5x and 6-3x?
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
The square is formed from a wire the length of 3x, which forms a perimeter of the same length. Because each side of the square is one fourth of the total perimeter (1 out of 4 equal sides), each side is 3x/4. The square of one side of a square is equal to the area of that square, so the area is (3x/4)2 = (9/16)x2.The answer is then A = (9/16)x2.
What is the area of a square with a side length of 4x^3
The area of square is : 9.0
Width = X Length = 3X Four sides to the perimeter: x + x + 3x + 3x = 8x 8x = 22 x = 2.75 3x = 8.25 The length is 8.25.
Suppose the side of the square is x cm.Then its perimeter is 4x cm.The perimeter of the square is 3 cm more than that of the triangleso the perimeter of the triangle is 4x - 3 cm.Also, if the side of the square is x cm, the side of the triangle must be x + 112 cm.Then its perimeter must be 3*(x + 112) = 3x = 336 cm.Equating the two expressions for the perimeter of the triangle,4x - 3 = 3x + 336therefore x = 339 cm.The square has sides of 339 cm and a perimeter of 1356 cm.The triangle has sides of 451 cm and a perimeter of 1353 cm.
call width x so length is 3x perimeter is (2*length)+(2*width) so perimeter is 8x
Let x be the side of the triangle. Thus 4(x-5) is the perimeter of the square.Balance by the perimeter relation,3x = 7+4(x-5)Solve for x,x = 13 inches
Consider a square with sides of length x cm whose area is x2 cm and perimeter is 4x cm. Next consider a rectangle with sides of 2x cm and x/2 cm. It area is 2x*x/2 = x2, the same as for the square. But its perimeter is 2*(2x+x/2) = 5x > perimeter of the square. Perimeter of 3x * x/3 = 62/3x cm. Perimeter of 100x * x/100 = 200.02x cm Perimeter of 1000000x * x/1000000 = 2000000.000002x cm. As you can see, it is possible to increase the perimeter without limit.
Find the perimeter of the triangle with sides of length x, 5x and 6-3x?
OK, so let's say the length of the base = x. The leg length = 3x, as it's three times the base length. As there are two legs and a base making up the perimeter, the perimeter = 10x. So 62 = 10x. 62/10 = 6.2, therefore x = 6.2 and the base = 6.2 inches. Hope this helps! If base = x and each leg = 3x, then the perimeter would be 7x instead of 10x as mentioned above. (3x + 3x +x = 7x). Hence, perimeter = 7x and the base (x) = 8.857 inches.
The perimeter is the sum of all of the sides of the triangle. If the shorter leg is x, the longer leg is 3x. The hypotenuse is then the square root of x^2 + 3x^2, or 2x. Then the perimeter is x + 3x + 2x, simplified, f(x) = 6x.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet