55 square centimeters
The surface area of a cylinder with a radius of 3.8cm and a height of 11cm is 353.37cm2
Side of a square= take out the square root Area=169cm ² Square root of 169= 13 Side= 13 cm²
A cube has 6 faces and each face is square, so the answer is 6*11*11 sq. cm.
The area of this square is 104 square feet.
Area is 584.24cm² Perimeter is 88cm
Well, darling, to find the area of a triangle with those side lengths, you can use Heron's formula. So, plug in those side lengths (a=8, b=11, c=15) into the formula, calculate the semi-perimeter, and then solve for the area. Voilà, you've got yourself the triangle's area.
88cm2, but it's a rectangle, not a square.
66cm2
55 square centimeters
94.985 or approximately 95 square centimeter.
pi*112 = 380 square cm
11cmThe area of the square is 121cm2. Since the area of a square is just one side squared, to find the length of one side take the square root of the area. In this case the square root of 121 is 11. So the answer is 11 cm.
11cm x 17.5cm = 192.5 square centimeters which is 29.837559675119 square inches.
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
The surface area of a cylinder with a radius of 3.8cm and a height of 11cm is 353.37cm2
The area cannot be 33 cm because the area is measured in SQUARE units of length. That is, square centimetres. The question, therefore, is based on a nonsensical premise. Assume though, that the area is 33 cm2. Then, if one side is 11 cm, the other must be 33/11 = 3 cm. Then the perimeter is 2*(11+3) = 2*14 = 28 cm.