Area = 1/2*(15+11)*7= 91 square units
Height: (62.5*2)/25 = 5
242
Area of the trapezoid: 0.5*(8+11)*10 = 95 square measurements
ok
It is (7 + 15)/2 = 11 units of length.
Height: (62.5*2)/25 = 5
242
Area = 0.5*(9 + 3)*11 = 0.5*12*11 = 66 sq cm
The area ( A ) of a trapezoid can be calculated using the formula ( A = \frac{1}{2} \times (b_1 + b_2) \times h ), where ( b_1 ) and ( b_2 ) are the lengths of the bases, and ( h ) is the height. For this trapezoid, the bases are 9 and 2, and the height is 6. Plugging in the values, we get ( A = \frac{1}{2} \times (9 + 2) \times 6 = \frac{1}{2} \times 11 \times 6 = 33 ). Thus, the area of the trapezoid is 33 square units.
Area of the trapezoid: 0.5*(8+11)*10 = 95 square measurements
The area ( A ) of a trapezoid can be calculated using the formula: [ A = \frac{1}{2} \times (b_1 + b_2) \times h ] where ( b_1 ) and ( b_2 ) are the lengths of the two bases, and ( h ) is the height (altitude). Substituting the given values, ( b_1 = 3 ) in, ( b_2 = 11 ) in, and ( h = 8 ) in: [ A = \frac{1}{2} \times (3 + 11) \times 8 = \frac{1}{2} \times 14 \times 8 = 56 \text{ square inches.} ] Thus, the area of the trapezoid is 56 square inches.
Area = 0.5*(17+11)*9 = 126 square inches.
area = 1/2 sum_of_bases x height = 1/2 (8 + 11) x 4 = 38 square units
1/2*(7+11)*height = 63 18*height = 126 height = 7 units of measurement
Area = 1/2*(sum of the parallel sides)*height IF IT GOT SOMETHING TOO DO WITH (21)(11)(27) THEN ITS 264
ok
It is (7 + 15)/2 = 11 units of length.