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What is the area of a trapezoid with sides 4 cm and 5 cm and height 3 cm?
Wiki User
∙ 8y ago
The formula for the area of a trapezoid is (sum of lengths of parallel sides)/2 x perpendicular height. Assuming the measurements given are the parallel sides and the perpendicular height the area would be (4+5)/2 x 3 = 13.5 square cm.
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoIf the parallel sides are 4 and 5 then area is: 0.5*(4+5)*3 = 13.5 square cm
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The area of an isosceles trapezoid is 54 square cm. The perimeter is 32 cm. If a leg is 7 cm long what is the height of the trapezoid?
Let its height be x:- Area of the isosceles trapezoid: 0.5*(sum of parallel sides)*height Perimeter: 32-7-7 =18 which is sum of parallel sides Area: 0.5*(18)*x = 54 Height: (54*2)/18 = 6 cm Check: 0.5*(18)*6 = 54 square cm
Find the area of a trapezoid with bases of 18 cm and 26 cm and a height of 11 cm?
242
A trapezoid has an area of 45 cm2 The two bases are 6 cm and 12 cm What is the height of the trapezoid?
The area of a trapezoid is equal to one half the product of the length of its height and the sum of its bases. So we have: A = (1/2)(h)(B + b) substitute what you know into the formula 45 cm^2 = (1/2)(h)(12 cm + 6 cm) 45 cm^2 = (1/2)(h)(18 cm) 45 cm^2 = (h)(9 cm) divide by 9 cm to both sides 5 cm = h Thus, the height is 5 cm.
What is the area of a trapezoid whose height is 18.5 cm and whose bases are 20 cm and 24 cm?
area=18.5*(20+24)/2=407cm
What is the volume of a trapezoid prism of height 6 cm The parallel sides of the base have lengths 7 cm and 4 cm The other sides of the base are each 4 cm The trapezoidal attitude measures 3.7 cm?
99.6 cm
The area of an isosceles trapezoid is 54 square cm. The perimeter is 32 cm. If a leg is 7 cm long what is the height of the trapezoid?
Let its height be x:- Area of the isosceles trapezoid: 0.5*(sum of parallel sides)*height Perimeter: 32-7-7 =18 which is sum of parallel sides Area: 0.5*(18)*x = 54 Height: (54*2)/18 = 6 cm Check: 0.5*(18)*6 = 54 square cm
What is the area of a trapezoid whose height is 12 cm and whose parallel sides measure 3.5 cm and 5.5 cm?
Area = 0.5*(3.5+5.5)*12 = 54 square cm
How do you find the height of a trapezoid if only the area and the parallel sides are given the sides are 12 cm and 19 cm respectively and there are two lines in the middle of the trapezoid?
We will take the height as unknown, so Unknown = X Area = 1/2 x X x (12 + 19) X = A/31 And there you have it. :D.
How do you find the area of a trapezoid with measurements of 8 cm 9 cm 14cm?
the area of a trapezoid is the height times (base 1 + base 2)
Find the area of a trapezoid with the bases of 6centimeters and 8centimeters with the height of 5centimeters?
Trapezoid Area = (1/2)(b1 + b2)(h) We have: b1 = 6cm b2 = 8 cm h = 5 cm Substitute the given values into the area formula: Trapezoid Area = (1/2)(b1 + b2)(h) Trapezoid Area = (1/2)(6 cm + 8 cm)(5 cm) Trapezoid Area = (1/2)(14 cm)(5 cm) Trapezoid Area = (7 cm)(5 cm) Trapezoid Area = 35 cm^2
Find the area of a trapezoid with bases of 18 cm and 26 cm and a height of 11 cm?
242
Find the are of a trapezoid with height 6cm and bases 8cm and 4cm?
Area = 1/2*(sum of parallel sides)*height Area = 1/2*(8+4)*6 = 36 square cm
A trapezoid has an area of 45 cm2 The two bases are 6 cm and 12 cm What is the height of the trapezoid?
The area of a trapezoid is equal to one half the product of the length of its height and the sum of its bases. So we have: A = (1/2)(h)(B + b) substitute what you know into the formula 45 cm^2 = (1/2)(h)(12 cm + 6 cm) 45 cm^2 = (1/2)(h)(18 cm) 45 cm^2 = (h)(9 cm) divide by 9 cm to both sides 5 cm = h Thus, the height is 5 cm.
What is the area of a trapezoid with base lengths 14 cm and 12 cm and a height of 8 cm?
The area of ANY trapezoid is [ 1/2 times (height) times (one base plus the other base) ].Knowing that, you can now find the area of not only that particular trapezoid, but ofevery trapezoid that you ever encounter for the rest of your life. The formula is notexpected to change. You are empowered !
What is the height of an isosceles trapezoid whose parallel sides add up to 66.6 mm and has an area of 22.1778 square cm showing work?
area_trapezoid =½ × sum_parallel_sides × perpendicular_height_between_them → height = 2 × area_trapezoid ÷ sum_parallel_sides 10 mm = 1 cm → height = 2 × 22.1778 cm² ÷ (66.6 ÷ 10 cm) = 6.66 cm
What is the area of a trapezoid whose height is 18.5 cm and whose bases are 20 cm and 24 cm?
area=18.5*(20+24)/2=407cm
What is the area of a trapezoid if base1 is 6 cm and base2 is 4cm?
Area = 1/2*(6+4)*height
