The area of triangle is : 24.0
The area is 12cm2
A = 24cm2
The lengths of the sides does not provide enough information to answer the question.
Area of a triangle = 1/2 * base * heightWe have,Area = 28 cm squared, base = 8cmthen,28 = 1/2 * 8 * h28 = 4*hh = 7cm
A rectangle that is 2cm by 4cm has an area of 8cm. It also has a perimeter of 12cm.
The area of rectangle is : 32.0
The area of triangle is : 8.0
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
The area of the triangle with these sides is found by Heron's formula, which states that: semiperimeter = (a + b + c) / 2 Area = √(s(s - a)(s - b)(s - c)) Then: semiperimeter = (6 + 8 + 4) / 2 cm = 9 cm Area = √(9(9 - 8)(9 - 6)(9 - 4)) cm² ≈ 11.6 cm²
What is the area of the triangle 10cm ,8cm and 6cm
The area of triangle is : 24.0
It does not have a circumference but its perimeter is: 4+6+8 = 18 cm
A triangle rectangle : S=bxh/2 b=8cm / h=4cm divided by two= 16cm2 A Square = 2 cm each side = 16 cm2
Draw a right angled triangle with legs of 4cm and 6cm
The area of triangle is : 44.0
If one side of the triangle is 8cm then the other side is 7cm because 0.5*8*7 = 28 square cm