The area of the triangle with these sides is found by Heron's formula, which states that:
semiperimeter = (a + b + c) / 2
Area = √(s(s - a)(s - b)(s - c))
Then:
semiperimeter = (6 + 8 + 4) / 2 cm = 9 cm
Area = √(9(9 - 8)(9 - 6)(9 - 4)) cm²
≈ 11.6 cm²
16 cm
What is the area of the triangle 10cm ,8cm and 6cm
yes
No because the dimensions given relate to an isosceles triangle.
Draw a right angled triangle with legs of 4cm and 6cm
It does not have a circumference but its perimeter is: 4+6+8 = 18 cm
That will be 192mls.
16 cm
No because it would be an isosceles triangle
The area of triangle is : 24.0
What is the area of the triangle 10cm ,8cm and 6cm
yes
No because the dimensions given relate to an isosceles triangle.
A = 24cm2
The area of triangle is : 24.0
22cm
Draw a right angled triangle with legs of 4cm and 6cm