The area of the triangle with these sides is found by Heron's formula, which states that:
semiperimeter = (a + b + c) / 2
Area = √(s(s - a)(s - b)(s - c))
Then:
semiperimeter = (6 + 8 + 4) / 2 cm = 9 cm
Area = √(9(9 - 8)(9 - 6)(9 - 4)) cm²
≈ 11.6 cm²
16 cm
yes
No because the dimensions given relate to an isosceles triangle.
Draw a right angled triangle with legs of 4cm and 6cm
This cant be answer because we need to know which is the height and which is the length .
It does not have a circumference but its perimeter is: 4+6+8 = 18 cm
That will be 192mls.
16 cm
No because it would be an isosceles triangle
The area of triangle is : 24.0
yes
No because the dimensions given relate to an isosceles triangle.
A = 24cm2
The area of triangle is : 24.0
22cm
To find the area of a triangle, you can use the formula: Area = 0.5 * base * height. In this case, the base is 8cm and the height is 4cm. Plugging these values into the formula, the area would be 0.5 * 8cm * 4cm = 16 square centimeters.
A=1/2(b)(h). So A=1/2(6cm)(4cm). A=12cm^2, or 12 squared centimeters.