The hypotenuse of 21 does not yield an integral value for the second leg.
The legs are 16 and the square root of 185, which is about 13.6
The area of the triangle is 1/2 (16 x 13.6) = about 108.8
212 = 162 + x2
x2 = 185
x = 13.6
The other sides are both 16. This is because in a 45-45-90 triangle the legs are congruent because of the isosceles triangle theorem, and also the hypotenuse of the triangle is equal to the leg times root 2. That is because of the 45-45-90 triangle theorem. So in a summary the legs are congruent and the hypotenuse is equal to the leg times root 2.
16 that dumb a s s below me almost made me fail. Apex...
The measure of the other leg is 12 feet. Use Pythagorean's theorem for right triangles: a2 + b2 = c2 where c is the length of the hypotenuse and a and b are the respective lengths of the legs of the triangle. Since the hypotenuse is 20 ft, c = 20 ft. We are also given that one of the legs is 16 ft, so a = 16 ft. We want to solve for the other leg, b. Algebraically manipulating Pythagorean's theorem, we get: c2 - a2 = b2. When we plug in the known values, this equation becomes: 202 - 162 = 144 = b2. Thus, b = √(144) = 12 ft.
a<sup>2</sup> + b<sup>2</sup> = c<sup>2</sup> I'm going to start with Pythagorean triples. 3-4-5 doesn't work with this triangle. But if we multiply each of the values by 4, we get 12-16-20. A perfect match if we multiply them again by 10! So the dimensions of the triangle are 120 (short leg), 160 (long leg), and 200 (hypotenuse).
Using trigonometry.Hypotenuse = 16So shorter leg = 16*sin(30) = 16*1/2 = 8Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.Using trigonometry.Hypotenuse = 16So shorter leg = 16*sin(30) = 16*1/2 = 8Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.Using trigonometry.Hypotenuse = 16So shorter leg = 16*sin(30) = 16*1/2 = 8Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.Using trigonometry.Hypotenuse = 16So shorter leg = 16*sin(30) = 16*1/2 = 8Longer leg = sqrt(162 - 82) = sqrt(192) = 8*sqrt(3) = 13.86 approx.Then Area = 1/2*legs = 1/2*8*13.86 = 55.43 square units.
This is impossible. A leg cannot be greater than the hypotenuse. (Unless the triangle is part imaginary)
The other leg length is 16.
Area of the right isosceles triangle: 0.5*16*16 = 128 square units
The other sides are both 16. This is because in a 45-45-90 triangle the legs are congruent because of the isosceles triangle theorem, and also the hypotenuse of the triangle is equal to the leg times root 2. That is because of the 45-45-90 triangle theorem. So in a summary the legs are congruent and the hypotenuse is equal to the leg times root 2.
Use Pythagoras' theorem: 202-122 = 256 Square root of 256 =16 Length of the other leg is 16 units.
Each leg length is 16 times square root of 2 or about 22,627 inches to 3 decimal places
The hypotenuse of a right triangle with legs 12 inches and 16 inches is: 20 inches.
The area is 960mm2To find the other angle you use pythagoras' theorem.682=602+x24624=3600+x2x2=1024x= 32The area of a triangle is half length by height:32/2 is 16. 16x60 = 960mm2
16 that dumb a s s below me almost made me fail. Apex...
It's 6,40312. 4²+5²= hypotenuse ² 16+25=hypotenuse ² 41=hypotenuse ² |√ 6,40312=hypotenuse
The measure of the other leg is 12 feet. Use Pythagorean's theorem for right triangles: a2 + b2 = c2 where c is the length of the hypotenuse and a and b are the respective lengths of the legs of the triangle. Since the hypotenuse is 20 ft, c = 20 ft. We are also given that one of the legs is 16 ft, so a = 16 ft. We want to solve for the other leg, b. Algebraically manipulating Pythagorean's theorem, we get: c2 - a2 = b2. When we plug in the known values, this equation becomes: 202 - 162 = 144 = b2. Thus, b = √(144) = 12 ft.
a<sup>2</sup> + b<sup>2</sup> = c<sup>2</sup> I'm going to start with Pythagorean triples. 3-4-5 doesn't work with this triangle. But if we multiply each of the values by 4, we get 12-16-20. A perfect match if we multiply them again by 10! So the dimensions of the triangle are 120 (short leg), 160 (long leg), and 200 (hypotenuse).