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The hypotenuse of 21 does not yield an integral value for the second leg.

The legs are 16 and the square root of 185, which is about 13.6

The area of the triangle is 1/2 (16 x 13.6) = about 108.8

212 = 162 + x2

x2 = 185

x = 13.6

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Q: What is the area of a triangle with a hypotenuse of 21 and a leg of 16?
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Related questions

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The measure of the other leg is 12 feet. Use Pythagorean's theorem for right triangles: a2 + b2 = c2 where c is the length of the hypotenuse and a and b are the respective lengths of the legs of the triangle. Since the hypotenuse is 20 ft, c = 20 ft. We are also given that one of the legs is 16 ft, so a = 16 ft. We want to solve for the other leg, b. Algebraically manipulating Pythagorean's theorem, we get: c2 - a2 = b2. When we plug in the known values, this equation becomes: 202 - 162 = 144 = b2. Thus, b = √(144) = 12 ft.


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