Area = 8.06 cm2.
all the angles in a triangle have to add up to 180. to find the missing angle : 180 - 32 - 58 = 90 90 is a right angle and since there is a right angle in the triangle, it is a right angled triange
The angles of a triangle must add to a total of 180 degrees, so if you have 27 and 58 as two of your angle measurements the rest is easy. 27+58 = 85 180-85 = 95 Your third angle will be 95 degrees.
Yes, acute isoceles triangles exist. An example is 61/61/58. The sum of the angles is 180, so it is a triangle.
The radius of the circle is 4.296739857 and its circumference is 27 feet rounded
Suppose the length is L and the breadth is B. Then since perimeter = 58, 2*(L+B) = 58 so that L+B = 29 that is L = 29-B Now Area = L*B = 204 That is (29-B)*B = 204 Or B2 - 29B + 204 = 0 which is equivalent to (B-12)*(B-17) = 0 So, using L+B = 29, L and B are 12 and 17.
It is a right angle triangle
Perimeter = 45+58+58 = 161 units of measurement
58
58
If the diameter is 58 feet then the area is 2,642 square feet. If the circumference is 58 feet then the area is 267.7 square feet.
All the angles are smaller than 90o, so triangle is acute triangle.
Not on a plane surface.
Cos(58) = 4/Hypotenuse so H = 4/Cos(58) = 7.55 units.
all the angles in a triangle have to add up to 180. to find the missing angle : 180 - 32 - 58 = 90 90 is a right angle and since there is a right angle in the triangle, it is a right angled triange
180 - (27 + 58)...
3rd angle is 180-27-58 = 95 degrees
The angles of a triangle must add to a total of 180 degrees, so if you have 27 and 58 as two of your angle measurements the rest is easy. 27+58 = 85 180-85 = 95 Your third angle will be 95 degrees.