30cm
30cm2
Find the area of 5cm 12cm 8cm
What is the area of a triangle with base 2cm and height 3cm
No because the sum of the smaller sides must be greater than the longest side
30 sq cm ((12 x 5)/2)
Area of a triangle = 1/2 (Base x Height) Example: Width 13cm, Height 5cm, Base 12cm then; Area=1/2(12cm x 5cm) Area=6cm x 5cm Area=30cm2
30cm
The area of a 12cm by 5cm right-angled triangle is: 42 cm2
If two sides of a triangle have lengths of 5cm and 12cm, then the third side can have any length that's more than 7cm and less than 17cm. If the third side is 13cm, then the triangle is a right triangle.
30cm2
this is 5cm (:
Find the area of 5cm 12cm 8cm
52 + 122 = 25 + 144 = 169 = 132 This calculation confirms that the three sides of length 5, 12 and 13 cm form a right angled triangle with the side of length 13cm being the hypotenuse.
I cut out the lengths to have a visual look at the problem and the answer is NO you cannot arrange 5cm, 12cm, and 19cm into a triangle. Even straightening out the lengths of 5cm and 12cm into a 180 degree angle will not measure out to the 19cm. You cannot have a side that is more than the length of the other two sides combined in a triangle.
2.4
The area would be 60 cm2