A single number does not constitute a sequence.
The geometric mean of 7 and 56 is 19.7989898732
35
35
It is sqrt(7*9) = sqrt(63) = 7.9373, approx.
7:3
11.27357
The 7th term is 7 x (-2)6 = 7 x 64 = 448
Well, honey, if the first term is 7 and the common ratio is 1.1, all you gotta do is multiply 7 by 1.1 three times to find the fourth term. So, 7 x 1.1 x 1.1 x 1.1 equals 9.697. So, darling, the fourth term of this geometric sequence is 9.697.
In a geometric sequence, the nth term can be calculated using the formula ( a_n = a_1 \cdot r^{(n-1)} ). Given that the first term ( a_1 = -14 ) and the common ratio ( r = \frac{1}{2} ), the 4th term is calculated as follows: [ a_4 = -14 \cdot \left(\frac{1}{2}\right)^{3} = -14 \cdot \frac{1}{8} = -\frac{14}{8} = -\frac{7}{4}. ] Thus, the 4th term in the sequence is (-\frac{7}{4}).
An example of an infinite geometric sequence is 3, 5, 7, 9, ..., the three dots represent that the number goes on forever.
To find the seventh term of a sequence, you need to identify the pattern or formula governing the sequence. If it's an arithmetic sequence, you can use the formula ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term, ( d ) is the common difference, and ( n ) is the term number. For a geometric sequence, use ( a_n = a_1 \cdot r^{(n-1)} ), where ( r ) is the common ratio. Substitute ( n = 7 ) into the appropriate formula to find the seventh term.
The numbers could be from the sequence with a(1) = -3 and the common ratio r = (-2)If so, thena(7) = -3*(-2)^6 = -3*64 = -192.Of course, it is entirely possible that the numbers do not form a geometric sequence but a polynomial sequence such asa(n) = (27*n^3 - 189*n^2 + 396*n - 240)/2 and if so, a(7) = 1266.
The numbers 2, 4, 7, 11 are neither strictly arithmetic nor geometric. In an arithmetic sequence, the difference between consecutive terms is constant, while in a geometric sequence, the ratio between consecutive terms is constant. Here, the differences between terms are 2, 3, and 4, suggesting a pattern of increasing increments. Following this pattern, the next two terms would be 16 (11 + 5) and 22 (16 + 6).
T(n) = 7*(-2)^(n-1) for n = 1, 2, 3, ...
first you need to write your equation. This is an exponential function so the equation would be- A(N)=a(b)^n-1 where a is the first term in the sequence (for you a=-14) b is the common ratio (for you b=1/2) and n= the number of term in your sequence (for you n=5, but it can be any number you want to find the nth sequence of.) Now take the equation a(n)=a(b)^n-1 and plug in your variables- Now your equation is a(5)=-14(1/2)^5-1 The first step to solving this is simplifying your exponent- so subtract 1 from five then your equation would read a(5)=-14(1/2)^4 Now solve the exponent then you would have a(5)=-14(1/16) then all you have to do is multiply a(5)=-7/8 So the fifth term in your sequence is -7/8 I hope this helped. :)
There are different answers depending upon whether the sequence is an arithmetic progression, a geometric progression, or some other sequence. For example, the sequence 4/1 - 4/3 + 4/5 - 4/7 adds to pi
It can be any number. Two numbers do not even determine whether the "sequence" is arithmetic, geometric or other.