A single number does not constitute a sequence.
The geometric mean of 7 and 56 is 19.7989898732
35
35
7:3
It is sqrt(7*9) = sqrt(63) = 7.9373, approx.
11.27357
The 7th term is 7 x (-2)6 = 7 x 64 = 448
Well, honey, if the first term is 7 and the common ratio is 1.1, all you gotta do is multiply 7 by 1.1 three times to find the fourth term. So, 7 x 1.1 x 1.1 x 1.1 equals 9.697. So, darling, the fourth term of this geometric sequence is 9.697.
In a geometric sequence, the nth term can be calculated using the formula ( a_n = a_1 \cdot r^{(n-1)} ). Given that the first term ( a_1 = -14 ) and the common ratio ( r = \frac{1}{2} ), the 4th term is calculated as follows: [ a_4 = -14 \cdot \left(\frac{1}{2}\right)^{3} = -14 \cdot \frac{1}{8} = -\frac{14}{8} = -\frac{7}{4}. ] Thus, the 4th term in the sequence is (-\frac{7}{4}).
An example of an infinite geometric sequence is 3, 5, 7, 9, ..., the three dots represent that the number goes on forever.
To find the 35th term of the sequence starting with -7 and -315, we first determine the pattern. The second term, -315, can be calculated as -7 multiplied by 45, suggesting a common ratio of 45. This implies the sequence is geometric, where the nth term can be expressed as ( a_n = a_1 \cdot r^{(n-1)} ), with ( a_1 = -7 ) and ( r = 45 ). Thus, the 35th term is ( a_{35} = -7 \cdot 45^{34} ).
To find the seventh term of a sequence, you need to identify the pattern or formula governing the sequence. If it's an arithmetic sequence, you can use the formula ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term, ( d ) is the common difference, and ( n ) is the term number. For a geometric sequence, use ( a_n = a_1 \cdot r^{(n-1)} ), where ( r ) is the common ratio. Substitute ( n = 7 ) into the appropriate formula to find the seventh term.
The numbers could be from the sequence with a(1) = -3 and the common ratio r = (-2)If so, thena(7) = -3*(-2)^6 = -3*64 = -192.Of course, it is entirely possible that the numbers do not form a geometric sequence but a polynomial sequence such asa(n) = (27*n^3 - 189*n^2 + 396*n - 240)/2 and if so, a(7) = 1266.
The numbers 2, 4, 7, 11 are neither strictly arithmetic nor geometric. In an arithmetic sequence, the difference between consecutive terms is constant, while in a geometric sequence, the ratio between consecutive terms is constant. Here, the differences between terms are 2, 3, and 4, suggesting a pattern of increasing increments. Following this pattern, the next two terms would be 16 (11 + 5) and 22 (16 + 6).
T(n) = 7*(-2)^(n-1) for n = 1, 2, 3, ...
first you need to write your equation. This is an exponential function so the equation would be- A(N)=a(b)^n-1 where a is the first term in the sequence (for you a=-14) b is the common ratio (for you b=1/2) and n= the number of term in your sequence (for you n=5, but it can be any number you want to find the nth sequence of.) Now take the equation a(n)=a(b)^n-1 and plug in your variables- Now your equation is a(5)=-14(1/2)^5-1 The first step to solving this is simplifying your exponent- so subtract 1 from five then your equation would read a(5)=-14(1/2)^4 Now solve the exponent then you would have a(5)=-14(1/16) then all you have to do is multiply a(5)=-7/8 So the fifth term in your sequence is -7/8 I hope this helped. :)
There are different answers depending upon whether the sequence is an arithmetic progression, a geometric progression, or some other sequence. For example, the sequence 4/1 - 4/3 + 4/5 - 4/7 adds to pi