The geometric mean of 7 and 56 is 19.7989898732
35
35
It is sqrt(7*9) = sqrt(63) = 7.9373, approx.
square root of 7 x 12, ie 9.165
11.27357
The 7th term is 7 x (-2)6 = 7 x 64 = 448
7, 7.7, 8.47, 9.317 Ie 7 x 1.1^3
An example of an infinite geometric sequence is 3, 5, 7, 9, ..., the three dots represent that the number goes on forever.
The numbers could be from the sequence with a(1) = -3 and the common ratio r = (-2)If so, thena(7) = -3*(-2)^6 = -3*64 = -192.Of course, it is entirely possible that the numbers do not form a geometric sequence but a polynomial sequence such asa(n) = (27*n^3 - 189*n^2 + 396*n - 240)/2 and if so, a(7) = 1266.
T(n) = 7*(-2)^(n-1) for n = 1, 2, 3, ...
first you need to write your equation. This is an exponential function so the equation would be- A(N)=a(b)^n-1 where a is the first term in the sequence (for you a=-14) b is the common ratio (for you b=1/2) and n= the number of term in your sequence (for you n=5, but it can be any number you want to find the nth sequence of.) Now take the equation a(n)=a(b)^n-1 and plug in your variables- Now your equation is a(5)=-14(1/2)^5-1 The first step to solving this is simplifying your exponent- so subtract 1 from five then your equation would read a(5)=-14(1/2)^4 Now solve the exponent then you would have a(5)=-14(1/16) then all you have to do is multiply a(5)=-7/8 So the fifth term in your sequence is -7/8 I hope this helped. :)
There are different answers depending upon whether the sequence is an arithmetic progression, a geometric progression, or some other sequence. For example, the sequence 4/1 - 4/3 + 4/5 - 4/7 adds to pi
It can be any number. Two numbers do not even determine whether the "sequence" is arithmetic, geometric or other.
The sequence, -7, -21, 63 could be generated by Un = 49n2 - 161n + 105 so when n = 9 the term would be 2625.
It is arithmetic because it is going up by adding 2 to each number.
There cannot be a common ratio for only one number.