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I could answer that for you in a snap if I knew the size of angle 'b'.

Without that information, no answer is possible.

Wait! There is an answer. Not a useful one, but an answer nonetheless.

The cosine of angle 'b' is the square root of [ 1 minus the square of the sine of angle 'b' ] .

You heard it here first.

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Q: What is the cosine of angle b?
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Related questions

If the cosine of angle B is 0.2536 in a right triangle how can I find the measure of ( acute ) angle B with just that information?

Angle of B is cos^-1*(0.2536) = 75.309 degrees to three decimal places


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Let the sides be a, b and c and their opposite angles be A, B and C Using the cosine rule angle A = 75.5 degrees Using the cosine rule angle B = 57.9 degrees Angle C muct be 46.6 degrees because there are 180 degrees in a triangle Cosine Rule: cos A = (b2+c2-a2)/(2*b*c)


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The cosine function is mathematical equation to determine the adjacent angle of a triangle. The cosine of an angle is the ratio of the length of the hypotenuse: so called because it is the sine of the co-angle.


What is given two sides and the included angle?

The cosine rule which is: a2 = b2+c2-2*b*c*cosine A This is used to find the third side of a triangle when the two other sides are known along with the angle between them. Used when the triangle is not a right angle.


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Your question is kind of confusing, but if you're asking what the angle between two unit vectors A and B is, then the answer is: the inverse cosine of the dot products of A and B.


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How can you solve for angle A when only side a and side b of a right triangle are given in trigonometric functions?

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