Your question is kind of confusing, but if you're asking what the angle between two unit vectors A and B is, then the answer is: the inverse cosine of the dot products of A and B.
<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
any length between 1.5 and 8.5 meters depending on the angle between the vectors. find the dot product of the two vectors to find the magnitude. e.g. two vectors a x b . y c z gives a.x+b.y+c.z= your final answer. The dots mean times by (btw)
Graphical Vector AdditionDraw your first vector. Then draw the tail (start) of your second vector at the tip (end) of your first vector. Then draw the tail of your third vector at the tip of you third vector (if it exists,) and so on. To find the resultant, draw a vector from the tail of the first vector to the tip of the last vector. The angle of the resultant will be between the resultant's tail and the first vector's tail. To find these values, it is recommended that you use a scale (e.g. 1cm:1m) and a protractor so that your values are accurate.Or, to do it mathematically (with 2 vectors):You have vector a with angle Ao, and vector b with angle Bo.To get vector c (resultant,) break the vectors up into their x and y components, then add the x and y components to find the x and y of the resultant. To find the magnitude of vector c, use Pythagoras's theorem, a2 + b2 = c2. To find the angle of c, use inverse tangent, tan-1(y/x)Example:Remember that sin = y and cos = x. Thus, to find the x component of a vector, use cos, and to find the y component of a vector, use sin.c = square root( (acosA + bcosB)2 + (asinA + bsinB)2 )angle of c = tan-1( (asinA + bsinB)/(bcosA + bcosB) )
For two vectors A and B, the scalar product is A.B= -ABcos(AB), the minus sign indicates the vectors are in the same direction when angle (AB)=0; the vector product is ABsin(AB). Vectors have the rule: i^2= j^2=k^2 = ijk= -1.
Given one vector a, any vector that satisfies a.b=0 is orthogonal to it. That is a set of vectors defining a plane orthogonal to the original vector.The set of vectors defines a plane to which the original vector a is the 'normal'.
The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.
<ab> = |a|*|b|*cos(x) where |a| is the length of the vector a, |b| is the length of the vector b, and x is the angle between them.
To find the angle between two vectors, you need to use this form: a ∙ b / (|ab|) = cos(θ) θ = arccos(a ∙ b / (|ab|)) where a and b are vectors. Compute the dot product and the norm of |a| and |b|. Then, compute the angle between the vectors.
any length between 1.5 and 8.5 meters depending on the angle between the vectors. find the dot product of the two vectors to find the magnitude. e.g. two vectors a x b . y c z gives a.x+b.y+c.z= your final answer. The dots mean times by (btw)
Given two vectors a and b, the area of a parallelogram formed by these vectors is:a x b = a*b * sin(theta) where theta is the angle between a and b, and where x is the norm/length/magnitude of vector x.
To determine the magnitude when displacement vectors have opposite directions, you need to find the difference between the magnitudes of the two vectors. This is done by subtracting the magnitude of the primary vector from the magnitude of the secondary vector. The result will give you the magnitude of the resultant displacement.
Graphical Vector AdditionDraw your first vector. Then draw the tail (start) of your second vector at the tip (end) of your first vector. Then draw the tail of your third vector at the tip of you third vector (if it exists,) and so on. To find the resultant, draw a vector from the tail of the first vector to the tip of the last vector. The angle of the resultant will be between the resultant's tail and the first vector's tail. To find these values, it is recommended that you use a scale (e.g. 1cm:1m) and a protractor so that your values are accurate.Or, to do it mathematically (with 2 vectors):You have vector a with angle Ao, and vector b with angle Bo.To get vector c (resultant,) break the vectors up into their x and y components, then add the x and y components to find the x and y of the resultant. To find the magnitude of vector c, use Pythagoras's theorem, a2 + b2 = c2. To find the angle of c, use inverse tangent, tan-1(y/x)Example:Remember that sin = y and cos = x. Thus, to find the x component of a vector, use cos, and to find the y component of a vector, use sin.c = square root( (acosA + bcosB)2 + (asinA + bsinB)2 )angle of c = tan-1( (asinA + bsinB)/(bcosA + bcosB) )
The angle between two vector forces of magnitude can be calculated using the dot product formula: θ = cos^(-1)((A·B) / (|A||B|)) where A and B are the magnitudes of the forces. This formula gives the angle in radians.
To add vectors tip to tail to find the resultant vector, place the tail of the second vector at the tip of the first vector. The resultant vector is the vector that starts at the tail of the first vector and ends at the tip of the second vector.
For two vectors A and B, the scalar product is A.B= -ABcos(AB), the minus sign indicates the vectors are in the same direction when angle (AB)=0; the vector product is ABsin(AB). Vectors have the rule: i^2= j^2=k^2 = ijk= -1.
Vectors can be added using the component method, where you add the corresponding components of the vectors to get the resultant vector. You can also add vectors using the graphical method, where you draw the vectors as arrows and then add them tip-to-tail to find the resultant vector. Additionally, vectors can be added using the trigonometric method, where you use trigonometry to find the magnitude and direction of the resultant vector.
To find the resultant of the two vectors, break each vector into its horizontal and vertical components. Then add these components separately to find the total horizontal and vertical components. Finally, use these components to calculate the magnitude and direction of the resultant vector using trigonometry.