First of all remember the two circular equations.
A = pi r^2
C = 2 pi r or C = pi d ; there fore 2r = d
Using the first eq'n
A = pi r^(2)
Then
r^(2) = A / pi
r = sqrt[A/pi] (The radius)
Substituting
r = sqrt( 36 pi/ pi )
Cancel down by 'pi'
r = sqrt(36)
r = 6
From the 2nd eq'n 2r = d
So 2(6) = 12 The diameter.
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We'll have to work backwards for this problem. Let's start with the area. The formula for the area of a circle is πr2. So to find the radius, our equation is now πr2=36π. We can divide both sides by π, so it becomes r2=36. Now we square root both sides, and it becomes r=6.
The diameter is twice the radius, so we multiply 6 by 2, and we find the answer. The diameter is 12.
The area of a circle, in terms of pie, with a diameter of 36 is: about 324pi
Area of a Circle = (pi)(r^2) Diameter = 2r If the diameter of the circle is 12, then the radius has to be 6. If the area of a circle is pi times the square of the radius, and the square of 6 is 36 (6x6), then the area of the circle is 36pi.
A 36-inch diameter circle has an area of: 1,017.9 square inches.* * * * *which is 7.07 square feet.
Area = pi*182 = 1017.876 square mm to 3 decimal places
The area of a circle with a diameter of two cm is about 3.1416 cm.