Suppose the area is a rectangle of length L ft and breadth B ft, so that L > B > 0.
Then Perimeter = 36 ft => L + B = 18 so that L = 18 - B
Then Area = 45 sq ft = L*B = (18 - B)*B
B2 - 18B + 45 = 0 => (B - 3)*(B - 15) = 0
So B = 3 => L = 15
or B = 15 => L = 3
Then L>B => Length = 15 ft, Breadth = 3 ft
All this assumes the area is a rectangle. It could, however, be an ellipse, or some other shape.
Area = 139.36 ft2
no. the square has 36 inch perimeter, and the pentagon has 45 inch perimeter
we know,area of rectangle = l * b perimeter= 45*30=1350 cm ^2
Yes; what about it?
It is: 50+45+50+45 = 190m
A square can't have a perimeter of 36 and an area of 45. If a square's perimeter is 36,then its area is 81. If a square's area is 45, then its perimeter is about 26.83 . (rounded)A figure whose perimeter is 36 and whose area is 45 is not a square. It's a rectanglethat measures (3 by 15).
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It is a 3 x 15 rectangle !
15x3 Area = 3x15=45 Perimeter = 3+3+15+15 = 36 This is solved algebraically by substituting the value of the length in terms of the width 2L + 2W = 36 L = 18-W L x W = 45 and (18-W) x W = 45 gives the equation W2+18W-45 = 0 (W-15)(W-3) = 0 and the width and length are 15 and 3
They are: 3 ft by 15 ft
Area = 139.36 ft2
Area = 3*45 = 135 square feet. Perimeter = 2*(3 + 45) = 2*48 = 96 feet.
no. the square has 36 inch perimeter, and the pentagon has 45 inch perimeter
No. Perimeter does not uniquely define surface area. Example: Perimeter = 36 If it's a square with sides = 9, then area = 92 = 81 If it's a rectangle measuring 12 by 6, then area = 72 If it's a rectangle measuring 15 by 3, then area = 45 If it's a rectangle measuring 16 by 2, then area = 32 etc. etc. etc. Each of these figures has the same perimeter, but they all have different areas.
10.5
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p = 75+75+45+45=240cm a = 75 x 45 = 3375cm