It is the square root of (-1-2)2+(2-6)2 = 5
Chat with our AI personalities
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
7.61
There are different ways to answer this question. The smallest separation observable with the unaided eye is about 0.01mm The smallest observable distance between two points is about 0.4 nm, which is the resolution of the most powerful Scanning Electron Microscope. The smallest theoretical distance between two particles would be the distance between two quarks inside a neutron, which is 10-18 m. The shortest mathematical distance would be 1/infinity.
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
The distance between two points on a coordinate plane is calculated using the distance formula: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, the coordinates of the two points are (7, 1) and (7, 3). Since the x-coordinates are the same, we only need to calculate the difference in the y-coordinates, which is (3 - 1) = 2. Plugging this into the distance formula gives us: Distance = √((0)^2 + (2)^2) = √4 = 2. Therefore, the distance between the two points is 2 units.