It is the square root of (-1-2)2+(2-6)2 = 5
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The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
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There are different ways to answer this question. The smallest separation observable with the unaided eye is about 0.01mm The smallest observable distance between two points is about 0.4 nm, which is the resolution of the most powerful Scanning Electron Microscope. The smallest theoretical distance between two particles would be the distance between two quarks inside a neutron, which is 10-18 m. The shortest mathematical distance would be 1/infinity.
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
The distance between two points on a number line is calculated by finding the absolute difference between their values. For the numbers 1 and 2, this is |2 - 1|, which equals 1. Therefore, the distance between 1 and 2 on a number line is 1 unit.
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula