Q: What is the distance of the point -15 8 from the origin of 0?

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The origin is located at the point whose coordinates are (0, 0) in 2-dimensional space or (0, 0, 0) in 3-dimensional space.

It is not true because the distance from (0, 0) to (2, 1) works out as the square root of 5 which is the circle's radius.

The origin (0, 0)

The origin is located at the point (0,0) on a two-dimensional xy-coordinate grid. Because Y = 0, this point is located on the x-axis. Because X = 0, this point is also located on the y-axis. To answer your question, the origin is located on both the x-axis and y-axis.

It is at the point of origin where the coordinate on the Cartesian plane is at (0, 0)

Related questions

Distance from (0, 0) to (5, 12) using distance formula is 13

The distance of a point from 0 is called its magnitude or absolute value. It is the measure of how far the point is from the origin on a number line or coordinate system.

It is the distance from the origin (point 0) to the given point, taking account of the scale.

To find the distance between the origin and the point (x,y) use Pythagoras on the right angled triangle which has the points (0, 0), (x, 0), (x, y) - the distance is the hypotenuse of the triangle and so has length: distance = √(x2 + y2) This can be extended to find the distance between any two points (x1, y1) and (x2, y2): distance = √((x2 - x1)2 + (y2 - y1)2) (for the original question (x1, y1) is the origin (0, 0) and the first formula results.)

Using the Law of Pythagoras, you get square root of (62 + 72).The distance between the origin and the point ( -6, 7 ) is ~9.22To find the distance, we use the distance formula.c2 = a2 + b2This is an adaptation from the Pythagorean theorem. In this case, a is the difference in x coordinates; b the difference in y.The Cartesian origin is at ( 0, 0 ). So...c2 = ( -6 - 0 )2 + ( 7 - 0 )2c2 = -62 + 72c2 = 36 + 49c2 = 85c =~ 9.22

at the origin

It is where the x and y axes intercept at right angles at the point of origin which is at (0, 0)

At the point of the origin which is at (0, 0)

It is at the point of origin which is at (0, 0)

work = force . distance. Since Force and distance are both vectors (work is the dot product), when the net distance = 0 (back to the point of origin), work = 0. That is, if the force is such that it moves the object back to the point of origin, it has done zero work. A centripetal force is one example. The distance = 0 when the object finishes one complete revolution. No work has been done since the beginning of the revolution.

The origin, in the Cartesian coordinate system, is the point with coordinates (0, 0). So, if you have another ordered pair, the ordered pair doesn't "have an origin"; rather, the origin is another point.

The origin is (0, 0), so the x-coordinate of the origin is 0. The point is located somewhere along the line x = 0, which is called the y-axis.