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What is the geometrical shape of equipotential surface due to single isolated charge?
Wiki User
∙ 9y ago
what is the geometrical shape of equipotential surface due to single isolated charge
Wiki User
∙ 9y ago
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Is it possible for equipotential lines to cross?
Equipotentials cannot cross because they relate to places with a given value for potential. Lines of force meet at the charge or point of mass. They can cross if they relate to the same potential. Think of two mountain chains of unvarying height crossing each-other.
Why is surface area important to the real world?
Some practical real world examples why surface area is important:If you want to paint a house, you need to know the surface area to determine how much paint to buy.If you want to plant grass on a dirt lot, you need to know the surface area to determine how much grass seat to use.If you want to sew a dress, you need to know the surface area of the dress (dress size) to know how much material you need.If you want to make money mowing lawns, you need to know the surface area of the lawn to know how much to charge for the work.If you want to put carpet in a living room, you need to know the surface area of the room to know how much carpet you will need.If you are making a label for a soup can company, you will need to know the surface area of the can.
How much to charge per square feet to install tile?
I charge $5 per foot with a 100 ft min.
What is the electron domain charge cloud geometry of ICl5?
The electron domain charge cloud geometry of ICI5 s usually positively charged. This is because the process involves the loss of electrons. The electron-domain charge-cloud geometry of ICl5 is octahedral.
What is the electron-domain charge-cloud geometry of BrI5?
Octahedral
Is any force is required to move a small charge on equipotential surface?
yes
What is the shape of equipotential surface due to a point charge?
concentric spherical surfaces
What is the amount of work done in moving a 100nc charge between two points 5 cm apart on an equipotential surface?
An equipotential surface has the same value of potential. Thus, work done would be zero. Work done = Charge X Potential difference
What is the work done in moving a charge of 10 nC between two points on an equipotent surface?
0, because its equipotential surface
Which is the locus of a point at which potential due to an isolated point charge is constant?
That's a spherical surface, with the charge at the center of the sphere.
What isolated conductor?
A conductor is not a wire or something, but it is a metallic object. it can store charge on it's surface. if it is connected to any other system which can dissipate or store energy, then it is not isolated. otherwise it is isolated.
What must be magnitude of an isolated change to have electric potential of 120 volts at a distance of 15 cm?
Don't you mean isolated charge?
What happens when an isolated conductor is statically charged?
The charge is evenly spread inside and outside
How do you draw isloted positive charge?
You can diagrammatically represent an isolated positive charge by drawing a small circle at the centre of the page such that straight lines are moving out of the charge - the lines represent the electric field surrounding the charge.
A Gaussian surface does not enclose a charge Does it mean that E equals 0 on its surface?
No.there can be electric field on the Gaussian surface even if the charge enclosed by it is zero.However ,net flux will be zero through the surface.
An isolated conducting sphere whose radius R equals 1M has a charge 1.1nc the energy density at the surface of sphere?
The energy density at the surface of a charged conductor is the surface charge density squared , divided by 2 x the permittivity of free space. The surface charge density is the charge divided by the area it sits on. So if, e = permittivity = 8.85 x 10^-12 CC/Nmm and D = surface charge density, and U = energy density and R = radius of sphere and q = charge on sphere, then; U = (1/2e) x D^2 where D = q/4piR^2 = 1.1 x 10^-9/(4 x 3.14 x 1) = 8.76 x 10^-11 , where 4piR^2 is the surface area of a sphere. So; D^2 = 76.7 x 10^-22 then ; U = (76.7 x 10^-22)/(17.7 x 10^-12) = 4.33 x 10^-10 Joules/mmm
What is the conservation of charge law from maxwell's equations?
The conservation of charge law from Maxwell's equations states that the current through any enclosed surface is equal to the time rate of charge within the surface.
