The hypotenuse of a right triangle with legs of 8 and 15 centimeters is the square root of (8 squared plus 15 squared), which is 17.
The hypotenuse is the square root of (82 +152) = 17.
Using Pythagoras' theorem the length of the hypotenuse is 17 units
The hypotenuse of a 30-60-90 triangle whose long leg is 13 centimeters is: 15.01 cm
The hypotenuse of a right triangle with legs of 8 and 10 is: 12.81
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
The hypotenuse of a right triangle with legs of 8 and 15 centimeters is the square root of (8 squared plus 15 squared), which is 17.
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
The length of the hypotenuse works out as 17 miles
17
The hypotenuse is the square root of (82 +152) = 17.
using the pythagorean thereom. a^2 + b^2 = c^2 in which a and b are your legs and c is your hypotenuse 8^2 + 15^2 = c^2 289=c^2 17 is the hypotenuse
Using Pythagoras' theorem the length of the hypotenuse is 17 units
Let c be the hypotenuse and use the Pythagorean theorem. 8^2 + 15^2 = c^2 64 + 225 = c^2 289 = c^2 17 = c
The hypotenuse of a 30-60-90 triangle whose long leg is 13 centimeters is: 15.01 cm
17 units using Pythagoras' theorem
do you have an angle measure? (if it is an equilateral triangle all legs will be 8 but i don't think this applies in your case)