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A 28 sided polygon is called an Icosikaioctagon This link should help: http://www.math.com/tables/geometry/polygons.htm
Assuming regular figure, exterior angle of n-sided polygon = 360/n degrees. In this case n = 16 so angle is 22.5 degrees and interior is 180 minus that figure ie 157.5 degrees. Alternatively you can use the formula for sum of interior angles of regular n-sided polygon which is (2n - 4) right angles. In this case 2n - 4 = 28 right angles which is 2520 degrees. Divided by 16 gives 157.5 degrees.
If it's a regular 28-agon then each interior angle is: (26*180)/28 = 167.'142857' degrees recurring decimals 0.'142857'
Sum of interior angles of ANY n-sided polygon is (2n - 4) right angles. In this case 28 x 90 ie 2520o
Ext.Angle = 360n (no. of sides_ Int.Angle = 180 - Ext.Angle. Substituting. Int.Angle = 180 - 360/n Hence Int.Angle = 180 - 360/28 Int.Anglr = 180 - 12.857.... Int.Angle = 167.142.... degrees.