Q: What is the exterior angle of a 28 sided polygon?

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A 28 sided polygon is called an Icosikaioctagon This link should help: http://www.math.com/tables/geometry/polygons.htm

Assuming regular figure, exterior angle of n-sided polygon = 360/n degrees. In this case n = 16 so angle is 22.5 degrees and interior is 180 minus that figure ie 157.5 degrees. Alternatively you can use the formula for sum of interior angles of regular n-sided polygon which is (2n - 4) right angles. In this case 2n - 4 = 28 right angles which is 2520 degrees. Divided by 16 gives 157.5 degrees.

If it's a regular 28-agon then each interior angle is: (26*180)/28 = 167.'142857' degrees recurring decimals 0.'142857'

Sum of interior angles of ANY n-sided polygon is (2n - 4) right angles. In this case 28 x 90 ie 2520o

Ext.Angle = 360n (no. of sides_ Int.Angle = 180 - Ext.Angle. Substituting. Int.Angle = 180 - 360/n Hence Int.Angle = 180 - 360/28 Int.Anglr = 180 - 12.857.... Int.Angle = 167.142.... degrees.

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A 28 sided polygon is called an Icosikaioctagon This link should help: http://www.math.com/tables/geometry/polygons.htm

The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°

It is a triacontagon, or 30-sided shape.The formula for one interior angle of a regular n-sided polygon is 180(n-2)/nwhere 180 (28) / 30 = 168*You can QUICKLY and EASILY find the answer using the formula for one exterior angle : it is 360/n360/30 = 12 and the interior angle is 180-12 = 168.The algebraic equation is(180-168) n = 360

sum of interior angles of a regular polygon = (n-2) x 180 degrees, where n = number of sides. Each interior angle - sum of exterior angles / the total number of angles (and there are the same number of angles as sides, so you can use sum / n) = ((28-2)*180)/28) = (26*180 / 28) = 4680 / 28 = 167.1429 degrees

Providing that it is a regular 28 sided polgon then each interior angle will measure: 1670 8' 34.29''

Assuming regular figure, exterior angle of n-sided polygon = 360/n degrees. In this case n = 16 so angle is 22.5 degrees and interior is 180 minus that figure ie 157.5 degrees. Alternatively you can use the formula for sum of interior angles of regular n-sided polygon which is (2n - 4) right angles. In this case 2n - 4 = 28 right angles which is 2520 degrees. Divided by 16 gives 157.5 degrees.

The interior angles add up to 4680 degrees

If it's a regular 28-agon then each interior angle is: (26*180)/28 = 167.'142857' degrees recurring decimals 0.'142857'

A 30 sided polygon contains 28 triangles.

cocokragon

icosikaioctagon

28