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12,600
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What is the sum of the measures of the interior angles of a regular 72 gon?
12,600 degrees -- and it doesn't matter whether the 72-gon is regular or not. The sum of the exterior angles (from an extension of each side to the next) of any polygon is always 360 degrees. Therefore the sum of the interior angles is always (number of sides) * 180 - 360. 72 * 180 - 360 = 70 * 180 = 12,600.
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 72?
540 degrees
What is the measure of the interior angles of a regular polygon if each exterior angle measures 72 degrees?
It is a 5 sided regular pentagon and each interior angle measures 108 degrees
Given an interior angle how do you find the sum of exterior angles of a polygon?
Given a shape as such... ______________________________________ / A=72 B=65 \ \ / \_C=105__________________D=110_______/ (sorta) You take the interior angles that you have and subtract them from 360 to get their supplementary angles, which would be the measure of the outside angles corresponding to the interior angles Measure of <A= 72- so 360- 72=288*; so the measure of the exterior angle corresponding to <A is 288* You can do the same thing for the rest of the angles in the polygon. Hope it helps...
What is the measure of an angle of a regular pentagon?
108 degrees. It would actually be 72 degrees because you take 360 and divide by 5 and get 72. ^_^ Actually it would be 108 degrees, because the sum of the interior angles of a pentagon is 540. ;]
