Since the "slices" of an equilateral hexagon are equilateral triangles, the Pythagorean theorem will solve this problem: A squared plus B squared equals C squared, where A and B are the sides at right angle to each other and C is the hypoteneuse (long side). Slice a 10 inch tall equilateral triangle down the middle. The height A is 10 inches; the base B (1/2 of A) is 5 inches. 10 squared equals 100; 5 squared equals 25. Therefore, the length of each side of the equilateral triangle is the square root of 125, or approximately 11.18 inches. This is also the length of the sides of the hexagon in question.
20
A decagon has ten sides, a hexagon has 6, a nonagon has nine, and a triangle has three. So 2 decagons, 1 hexagon, 4 nonagons, and 2 triangles have 2*10 + 1*6 + 4*9 + 2*3 = 20 + 6 + 36 + 6 = 68 sides altogether.
A triangle with side a: 36, side b: 20, and side c: 20 meters has an area of 156.92 square meters.
Since the cube root of 8000 is 20, then each side has length 20.
Using Pythagoras' theorem the length of the remaining side is 40 meters
The area of a hexagon with a given side of 20 is 1,039
120cm (six sides x 20 = 6 x 20 = 120)
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
20
The hexagon will consist of 6 equilateral triangles having sides of 20 cm and so:- Area of the regular hexagon: 0.5*20*20*sin(60 degrees)*6 = 1039 square cm rounded
Icosikaihexagon Icosikai is 20 and hexagon is 6
But a hexagon has only 6 points while an octagon has 8 points.
$20
An icosagon
3 rhombuses will fit into one Hexagon...so it would be 20x3
knowing the size of a wrestling ring depends on the shape of the ring, if it square then it is 18 feet, if it is an hexagon then it is 20 - 21 feet wide.
None anymore, the classic 20 hexagon and 12 pentagon shape is no longer used.