It is k times the perimeter of eh where k is the constant ratio of the sides of abcd to the corresponding sides of efgh.
It is k times the length of Ad where k is the constant of proportionality between the two shapes.
The question cannot be answered without information about the relative sizes of the two polygons.
Oh, dude, Canada is like super huge, eh? The length of Canada from east to west is about 4,634 kilometers, and the width from north to south is around 5,514 kilometers. So, yeah, it's like really big, but who's measuring, right?
The secret of Kappa Alpha Psi: Fraternity, Knowledge, Fidelity. The words are actually written at the bottom of their shield. Not too smart, eh?
It is k times the perimeter of eh where k is the constant ratio of the sides of abcd to the corresponding sides of efgh.
It is k times the length of Ad where k is the constant of proportionality between the two shapes.
The question cannot be answered without information about the relative sizes of the two polygons.
the length of a Ball pen is centimeter
Vertices: E (-2, -1); F (-4, 3); G (1, 5); and H (3, 1).Plot these points in a coordinate system and connect them. The quadrilateral EFGH is formed.The slope of the line where the side EF lies is -2.[(3 - -1)/(-4 - -2)] = 4/-2 = -2The slope of the line where the side HG lies is -2.[(5 - 1)/(1 - 3)] = 4/-2 = -2Thus the opposite sides EF and HG of the quadrilateral EFGH are parallel.The slope of the line where the side EH lies is 2/5.[(1 - -1)/(3 - -2)] = 2/5The slope of the line where the side FG lies is 2/5.[(5 - 3)/(1 - -4)] = 2/5Thus the opposite sides EH and FG of the quadrilateral EFGH are parallel.Since any of the slopes is not a negative reciprocal of the others, then the two adjacent sides are not perpendicular. And if we look at the diagram, we clearly see that this quadrilateral can be a parallelogram.The length of the side EF is square root of 20.Square root of [(5 - 1)^2 + (1 - 3)^2] = Square root of [4^2 + (-2)^2] = Square root of 20.The length of the side HG is square root of 20.Square root of [(3 - -1)^2 + (-4 - -2)^2] = Square root of [4^2 + (-2)^2] = Square root of 20.Thus, the opposite sides EF and HG of the quadrilateral EFGH are congruent.Two other parallel sides, EH and FG, must be congruent also, since they intersect two other parallel lines (their length is equal to square root of 29).So we verified that the quadrilateral EFGH is a parallelogram.
Since E is inside square ABCD and X is on side CD, then EX must be less than EY since X is closer to the interior of the square. Since EY crosses side AD and E is inside ABCD, it proves that E must lie on side BD as only one point could be both on BD and inside ABCD.
Eh, what? lol? Noone 90%+ similar but 89%-. Those are: Saturn, Neptune and Uranus.
di ko ngarin alam eh*
Le due lingue italiane e spagnole sono simili.(leh doo-eh leen-gweh ee-tal-ian-eh eh spah-nyol-eh soh-noh see-mee-lee)
Stop callin', stop callin', I don't wanna think anymore! I left my hand and my heart on the dance floor. Stop callin', stop callin', I don't wanna talk anymore! I left my hand and my heart on the dance floor. Eh, eh, eh, eh, eh, eh, eh, eh, eh… Stop telephonin' me! Eh, eh, eh, eh, eh, eh, eh, eh, eh… I'm busy! Eh, eh, eh, eh, eh, eh, eh, eh, eh… Stop telephonin' me! Eh, eh, eh, eh, eh, eh, eh, eh, eh… Stop callin', stop callin', I don't wanna think anymore! I left my hand and my heart on the dance floor. Stop callin', stop callin', I don't wanna talk anymore! I left my hand and my heart on the dance floor. Eh, eh, eh, eh, eh, eh, eh, eh, eh… Stop telephonin' me! Eh, eh, eh, eh, eh, eh, eh, eh, eh… I'm busy! Eh, eh, eh, eh, eh, eh, eh, eh, eh… Stop telephonin' me! Eh, eh, eh, eh, eh, eh, eh, eh, eh…
d ko ngah alm eh
'Ai' which I think sounds similar to the Canadian 'eh' expression.