It can be any length greater than 6 cm and less than 20 cm.
The third side can have any value in the range (2 cm, 16 cm).
7cm
What is the are for a rectangle of 13cm and 7cm
Perimeter = 4*7 = 28 cm
It might be pythagoras therom but it can only be Pythagoras when the traingle has a right angle. If it does then try to work it out using phythagoras. If the angle between the given sides is B, then: b2 = a2 + c2 - 2ac cos B ⇒ b2 = (7 cm)2 + (13 cm)2 - 2 x 7 cm x 13 cm x cos B ⇒ b = √(218 - 182 cos B) cm If it is a right angle triangle, with B the right angle, cos B = cos 90o = 0 and this becomes Pythagoras making the side: b = √218 cm ≈ 14.76 cm If there is a right angle, not between the 7 cm and 13 cm, then the 13cm side is the hypotenuse (as the hypotenuse must be the longest side) and the other side is: b = √(132 - 72) cm = √120 cm ≈ 10.95 cm
7 cm(7cm x 7 cm x 7cm) = 343 cm3
The third side can have any value in the range (2 cm, 16 cm).
7cm
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
A square has four equal sides. So the side length is 13 cm. The area, 13 cm x 13 cm, is 169 square centimetres.
It is: 4*7 = 28 square cm
9 cm
256 = 162; 16 - 7 = 9 cm
The width is 10.5 cm.
you have to do 7 squared + 13 squared = x squared. 7 squared is 49 + 13 squared which is 169. 169+49=x squared. 218= x squared. The square root of 218 is about 14.765. So the answer should be about 15cm if the missing side is the hypotnus (the diaganal side)
13 cm
To create a triangle, the sum of the two shorter sides must be greater than the third side. If the side of length 29 cm is the longest side then the missing side must be greater than 29 cm - 13 cm = 16 cm If the missing side is the longest side then the missing side must be less than 29 cm + 13 cm = 42 cm Thus any length that is greater than 16 cm and less than 42 cm. Examples include: 17 cm, 18 cm, 20 cm, 36 cm, 41cm