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If the sum of the interior angle measures of a polygon is 1260 how many sides does the polygon have?
We solve the equation for n... since the sum of the interior angles is 180(n-2) where n is the number of sides of the polygon. So we have: 180(n-2)=1260 n-2=7 n=9 So 9 sides
What is the sum of angles in a 9-sided polygon?
(n-2)*180 = sum of interior angles of any polygon where n = number of sides. (9-2)*180 = 1260 degrees.
How many sides does a polygon have if the sum of the measures of its interior angles is 1080?
the sum of the interior angles of a polygon is 180(n-2), where n is the number of sides.1080 = 180(n-2)6 = n-2n = 8The polygon has 8 sides, it is an octagon.
If the measure of a vertex angle of a regular polygon is 162 degrees how many sides does the polygon have?
All vertex angles (also called "interior angles") of a regular polygon have equal measures. If this regular polygon has n sides, then the sum of all the interior angles is 162° times n. The sum of the measures of all the interior angles of any polygon with n sides is (n-2) times 180°. So we have this equation 162n=(n-2)(180) which has solution n=20. So the polygon has 20 sides. Edwin McCravy
If the sum of the measures of the interior angles of a polygon is 1980 how many sides does it have?
The formula for the sum of the angles of an interior polygon is 180(n-2), where n is the number of sides, so then you solve 180(n-2) = 1980. (n-2) = 11 n = 13. So the polygon has 13 sides.
