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What is the sum of the measures of the interior angles of a regular polygon is each exterior angle measures 120?
To find the sum of the measures of the interior angles of a regular polygon with each exterior angle measuring 120 degrees, we first determine the number of sides in the polygon. The sum of exterior angles of any polygon is always 360 degrees, so the number of sides ( n ) can be calculated as ( n = \frac{360}{120} = 3 ). Since it is a triangle, the sum of the interior angles is given by the formula ( (n - 2) \times 180 ) degrees, which for a triangle (3 sides) is ( (3 - 2) \times 180 = 180 ) degrees. Thus, the sum of the measures of the interior angles is 180 degrees.
How many side are there in a polygon if one of the interior angles measures 108?
A polygon with any number of sides can have an interior angle measuring 108 degrees.
What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
The sum of the measures of the angles in a triangle is 180 degrees In a quadrilateral the sum is 360 degrees find an equation relating n the number of sides in a polygon and S the sum of angles?
S=180n-360
What is the formula used to calculate the number of sides in a polygon using its angle measures?
Let S be the sum of the measures of all the interior angles, in degrees. Then the number of sides is S/180 + 2.
What is the sum of the measures of the exterior angles of a regular polygon with ten sides?
The sum of the measures of the exterior angles of any polygon, regular or irregular, is always 360 degrees. In a regular polygon with ten sides, each exterior angle measures 360 degrees divided by the number of sides, which in this case is 36 degrees. Therefore, the sum of the measures of the exterior angles of a regular decagon is 10 multiplied by 36 degrees, which equals 360 degrees.
What is the sum of the measurs of the exterior angles of a convex polygon with 17 sides?
360 degrees. The sum of the measures of the exterior angles any convex polygon will always be 360 degrees. The formula for finding the sum of the measures of the interior angles is 180(n-2) when n= the total number of sides the polygon has.
What is the sum of the measures of the exterior angles of a 23-gon?
What is the sum of the exterior angles of a 23 gon
What is the sum of the measures of the interior angles of a regular polygon is each exterior angle measures 120?
To find the sum of the measures of the interior angles of a regular polygon with each exterior angle measuring 120 degrees, we first determine the number of sides in the polygon. The sum of exterior angles of any polygon is always 360 degrees, so the number of sides ( n ) can be calculated as ( n = \frac{360}{120} = 3 ). Since it is a triangle, the sum of the interior angles is given by the formula ( (n - 2) \times 180 ) degrees, which for a triangle (3 sides) is ( (3 - 2) \times 180 = 180 ) degrees. Thus, the sum of the measures of the interior angles is 180 degrees.
How many side are there in a polygon if one of the interior angles measures 108?
A polygon with any number of sides can have an interior angle measuring 108 degrees.
What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
What is the number of sides of a regular polygon if one of its exterior angles measures 24 degrees?
It is: 360/24 = 15 sides
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
What is the number of sides of a regular polygon if one of its exterior angles measures 8 degrees?
45 sides 360/8 = 45
The sum of the measures of the angles in a triangle is 180 degrees In a quadrilateral the sum is 360 degrees find an equation relating n the number of sides in a polygon and S the sum of angles?
S=180n-360
What is the formula used to calculate the number of sides in a polygon using its angle measures?
Let S be the sum of the measures of all the interior angles, in degrees. Then the number of sides is S/180 + 2.
What is the sum of the measures of the exterior angles of a polygon?
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
