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As the number of sides in a regular polygon increases what happens to the measure of an interior angle?
As the number of sides in a regular polygon increases, the angle increases. This occurs as a function where each interior angle measures (180*(n-2)) / n, where n is the number of sides.
How do you find a number of sides of a polygon with the measure of its interior angle?
If its a regular polygon then 180-interior angle and divide the answer into 360 which will give the number of sides of the polygon.
What is the sum of the interior angle measures of a 21-sided polygon?
The sum of the interior angles of a polygon is 2n - 4 right angles where n is the number of sides. When n = 21 then 2n - 4 = 42 - 4 = 38 right angles = 38 x 90 = 3420°. NOTE : If the polygon is a regular polygon then each interior angle measures 3420 ÷ 21 = 162.86°.
Work out the number of sides of a regular polygon with the interior angle of 178?
If each interior angle is 178 degrees then the regular polygon will have 180 sides.
What is the number of sides of a regular polygon if its sum of interior polygon is 5760?
It will have 34 sides
What is the number of sides of a regular polygon if one interior angle measures 90?
A four-sided regular polygon (square or rectangle) has 900 interior angles.
What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
What is the number of sides of a regular polygon if one interior angle measures 108?
5 sides and it is a regular pentagon
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
Which polygon has the largest interior angle?
The polygon with the largest interior angle is a regular polygon, specifically a regular polygon with the greatest number of sides. In a regular polygon, all interior angles are equal, and the formula for calculating the interior angle of a regular polygon is (n-2) * 180 / n, where n is the number of sides. As the number of sides increases, the interior angle also increases. Therefore, a regular polygon with a very large number of sides will have the largest interior angle.
As the number of sides in a regular polygon increases what happens to the measure of an interior angle?
As the number of sides in a regular polygon increases, the angle increases. This occurs as a function where each interior angle measures (180*(n-2)) / n, where n is the number of sides.
What is the number of sides of a re gular polygon if one interior angle measures 108?
A polygon with interior angle measures of 108 would be a pentagon
Which regular polygon has interior angles with measures greater than 130?
For the interior angle of a regular polygon to be greater than 130° then the exterior angle must be less than 50°. The exterior angles of a regular polygon total 360°. 360/50 = 7.2 ....this needs to be rounded up to the next whole number. Therefore a regular polygon with 8 or more sides has interior angles measuring 130° or greater.
How do you find a number of sides of a polygon with the measure of its interior angle?
If its a regular polygon then 180-interior angle and divide the answer into 360 which will give the number of sides of the polygon.
What is the number of sides of a regular polygon if one angle measures 140 degrees?
Since the interior angle measure of the regular polygon is 140⁰, its exterior angle measure is 180⁰ - 140⁰ = 40⁰. Since the sum of the exterior angle measures is 360⁰, the polygon has 360⁰/40⁰ = 9 sides.
What is the sum of the interior angle measures of a 21-sided polygon?
The sum of the interior angles of a polygon is 2n - 4 right angles where n is the number of sides. When n = 21 then 2n - 4 = 42 - 4 = 38 right angles = 38 x 90 = 3420°. NOTE : If the polygon is a regular polygon then each interior angle measures 3420 ÷ 21 = 162.86°.
Work out the number of sides of a regular polygon with the interior angle of 178?
If each interior angle is 178 degrees then the regular polygon will have 180 sides.
