Well, if the area is 48, we can't really find the perimeter without more information. The perimeter depends on the shape of the figure, so unless you tell me if it's a square, rectangle, or some other shape, I can't give you a precise answer. So, spill the beans and give me more details if you want a proper response, honey.
144 cm2
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
It is the square root of 48 times 4 which is about 27.713 rounded to three decimal places
10 cm
Any number greater than 24.56 cm (approx). A circle, with a perimeter of 24.56 cm has an area of 48 cm2. A polygon with very many sides will approximate the circle. At the other extreme, suppose L ≥ 4*sqrt(3) = 27.71 cm and let W = 48/L Then the area of a rectangle with length L and width W is L*W = L*(48/L) = 48 cm2. The perimeter is 2*(L+48/L) cm. There is no maximum value for L and so, by making the rectangle thinner and longer, the perimeter can be increased to any number of your choosing.
A square with a perimeter of 48 meters has an area of 144 meters squared.
It is: 4*12 = a perimeter of 48 units
Side of the square = 1/4 of the perimeter = 12. Area = side2 = 144 .
144 cm2
48 inches.
144 in2
It is 48 cm.
2*24
It is 48 cm
Perimeter = 12+12+12+12 = 48 feet
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
The area of square is : 2304.0