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Q: What rectangle with the perimeter of 52 but has a different area of 48?

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If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

Well, L=6 and W=18If you do the math you get (6*2)+(18*2)=12+36=48Your final answer 48 yd. The perimeter is 48 yd.

If it's a rectangle, 48 m.

112 inches

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If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.

28 inches

maybe

You might want to investigate the rectangle that measures [ 6 by 8 ].

7 x 17

What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units

Anything greater than 27.713cm (4 x √48).

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

Of course, there are infinite possible answers to your question, but I will give two possible answers since that is what you asked for. If the rectangle is 1 ft X 48 ft, then the perimeter would be 98 ft. If the rectangle is 6 ft X 8 ft, then the perimeter would be 28 feet.

In whole numbers, the greatest perimeter would be a rectangle 48 x 1, resulting in a perimeter of 98m.

The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.

I thought circumference is only with circles Absolutely correct, but even if you consider the perimeter, which is conceptually similar, there is no answer. A rectangle with an area of 24 could be 4*6 with a perimeter of 20 or it could be 1*24 with a perimeter of 50 or 0.5*48 with a perimeter of 97 etc

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