2*24
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
Well, L=6 and W=18If you do the math you get (6*2)+(18*2)=12+36=48Your final answer 48 yd. The perimeter is 48 yd.
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
112 inches
48-ft
If the rectangle is a square, the perimeter is 48 cm. If not, there are a lot of possibilities.
28 inches
maybe
You might want to investigate the rectangle that measures [ 6 by 8 ].
7 x 17
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
Anything greater than 27.713cm (4 x √48).
Of course, there are infinite possible answers to your question, but I will give two possible answers since that is what you asked for. If the rectangle is 1 ft X 48 ft, then the perimeter would be 98 ft. If the rectangle is 6 ft X 8 ft, then the perimeter would be 28 feet.
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
I thought circumference is only with circles Absolutely correct, but even if you consider the perimeter, which is conceptually similar, there is no answer. A rectangle with an area of 24 could be 4*6 with a perimeter of 20 or it could be 1*24 with a perimeter of 50 or 0.5*48 with a perimeter of 97 etc
No, 12x4 = 48 sq meters. 13x3=39 sq meters.
In whole numbers, the greatest perimeter would be a rectangle 48 x 1, resulting in a perimeter of 98m.